The reaction of nitroprusside anion with sulp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction between sodium nitroprusside $(Na_2[Fe(CN)_5NO])$ and sulphide ion $(S^{2-})$ is a standard test for the detection of sulphur.The rea

Vedclass · Accepted Answer

the tetranionic complex of iron $(II)$ coordinating to one $NOS^{4-}$ ion

Vedclass · Answer

(A) The reaction between sodium nitroprusside $(Na_2[Fe(CN)_5NO])$ and sulphide ion $(S^{2-})$ is a standard test for the detection of sulphur.The reaction is as follows:$Na_2S + Na_2[Fe(CN)_5NO] \rightarrow Na_4[Fe(CN)_5NOS]$This complex dissociates in solution as:$Na_4[Fe(CN)_5NOS] \rightleftharpoons 4Na^+ + [Fe(CN)_5NOS]^{4-}$The resulting complex $[Fe(CN)_5NOS]^{4-}$ is a tetranionic complex of iron $(II)$ where the $NO^+$ ligand is replaced by $NOS^{3-}$ (or effectively coordinates as $NOS^{3-}$ to the $Fe^{2+}$ center),resulting in a deep purple colouration.

The reaction of nitroprusside anion with sulphide ion gives purple colouration due to the formation of

Similar Questions

Identify the highest field strength ligand from the following.

Which of the following factors tends to increase the stability of metal ion complexes?

$A$ solution contains $2.675 \ g$ of $CoCl_3 \cdot 6NH_3$ $(M = 267.5 \ g/mol)$. When passed through a cation exchanger,the chloride ions liberated are treated with excess $AgNO_3$ to yield $4.78 \ g$ of $AgCl$ $(M = 143.5 \ g/mol)$. What is the formula of the coordination compound?

Based on the given stability constants (hypothetical values),predict which is the strongest ligand?

Select the correct statement regarding the $[Ni(DMG)_2]$ complex compound.

Vedclass Test Series

Exam Paper Generator

Online Exam Module