What will be the energy of an electron emitte | vedclass

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(B) The energy difference $\Delta E$ for an electron transition from the ground state $(n_1 = 1)$ to an excited state $(n_2 = n)$ is given by the Rydb

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$Rhc(1 - n^{-2})$

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(B) The energy difference $\Delta E$ for an electron transition from the ground state $(n_1 = 1)$ to an excited state $(n_2 = n)$ is given by the Rydberg formula for energy: $\Delta E = E_n - E_1 = Rhc \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$ Substituting $n_1 = 1$ and $n_2 = n$: $\Delta E = Rhc \left( \frac{1}{1^2} - \frac{1}{n^2} \right)$ $\Delta E = Rhc (1 - n^{-2})$

What will be the energy of an electron emitted from the ground state to the $n^{th}$ orbit?

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