Identify Y in the following reaction sequence | vedclass

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(B) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2 + HCl$ at $0-5^{\circ}C$ to form benzene diazonium chloride $(

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Benzene

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(B) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2 + HCl$ at $0-5^{\circ}C$ to form benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$,which is $X$.$2$. Benzene diazonium chloride $(X)$ reacts with hypophosphorous acid $(H_3PO_2)$ and water to undergo reduction,yielding benzene $(C_6H_6)$ as the final product $Y$.Therefore,$Y$ is benzene.

Identify $Y$ in the following reaction sequence:
$C_6H_5NH_2$ $\xrightarrow[5^{\circ}C]{NaNO_2 + HCl} X$ $\xrightarrow{H_3PO_2 / H_2O} Y$

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Identify $Y$ in the following reaction sequence:$C_6H_5NH_2$ $\xrightarrow[5^{\circ}C]{NaNO_2 + HCl} X$ $\xrightarrow{H_3PO_2 / H_2O} Y$