Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound:
- Ahydrazobenzene
- Bazobenzene
- Caniline
- Dphenyl hydroxyl amine
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When primary amines are treated with $HCl$,the product obtained is
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$CH_3NH_2 \xrightarrow[\Delta]{CH_3I} (CH_3)_4N^{+}I^{-}$
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