Which of the following is not an A.P.? | vedclass

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(C) An Arithmetic Progression $(A.P.)$ is a sequence of numbers in which the difference between any two consecutive terms is constant. This constant d

Vedclass · Accepted Answer

$1, 0, 1, 0, \ldots$

Vedclass · Answer

(C) An Arithmetic Progression $(A.P.)$ is a sequence of numbers in which the difference between any two consecutive terms is constant. This constant difference is called the common difference $(d)$.For option $A$: $0 - 1 = -1$,$-1 - 0 = -1$,$-2 - (-1) = -1$. Since the common difference is constant $(d = -1)$,it is an $A.P.$For option $B$: $6 - 7 = -1$,$5 - 6 = -1$,$4 - 5 = -1$. Since the common difference is constant $(d = -1)$,it is an $A.P.$For option $C$: $0 - 1 = -1$,but $1 - 0 = 1$. Since the difference is not constant $(-1 
eq 1)$,it is not an $A.P.$For option $D$: $-9 - (-10) = 1$,$-8 - (-9) = 1$,$-7 - (-8) = 1$. Since the common difference is constant $(d = 1)$,it is an $A.P.$Therefore,the sequence $1, 0, 1, 0, \ldots$ is not an $A.P.$

Which of the following is not an $A.P.$?

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