Coding-Decoding Questions in English

(B) To find the code for 'summer',compare the given statements:
$1$. From statement $(B)$,'to nic re' means 'summer is hot'.
$2$. From statement $(C)$,'re pic boo' means 'winter and summer'.
$3$. Comparing $(B)$ and $(C)$,the common word is 'summer' and the common code is 're'.
$4$. Therefore,the code for 'summer' is 're'.

(C) Let us analyze the codes:
$1$. From $(A)$ and $(B)$: 'nic' = 'is'.
$2$. From $(A)$ and $(C)$: 'pic' = 'winter'.
$3$. From $(B)$ and $(C)$: 're' = 'summer'.
$4$. From $(A)$: 'vie' = 'cold'.
$5$. From $(D)$: 'vic' = 'cold' (Wait,'vie' and 'vic' are different codes for 'cold').
Actually,the question implies that to decode the language,we need specific sets. Statement $(A)$ and $(B)$ provide redundant information regarding the mapping of 'is','winter',and 'cold'. Specifically,statement $(D)$ introduces new words 'nights','are','tho',and 'pa' which cannot be decoded with the existing set,making it irrelevant to the primary decoding task of the first three statements. Thus,both $(A)$ and $(D)$ are superfluous for the core logic.

(C) $1$. Compare statement $(A)$ 'pit na som' (bring me water) and $(B)$ 'na jo tod' (water is life). The common word is 'water' and the common code is 'na'. Thus,'na' = 'water'.
$2$. Compare statement $(B)$ 'na jo tod' (water is life) and $(D)$ 'jo lin hot' (life and death). The common word is 'life' and the common code is 'jo'. Thus,'jo' = 'life'.
$3$. In statement $(B)$,we have 'na jo tod' representing 'water is life'. Since 'na' = 'water' and 'jo' = 'life',the remaining code 'tod' must represent 'is'.
Therefore,the correct option is $(C)$.

(B) To decode the language,we analyze the common words:
$1$. From $(A)$ and $(B)$,'na' is common,and 'water' is common. So,'na' = 'water'.
$2$. From $(A)$ and $(C)$,'pit' is common,and 'me' is common. So,'pit' = 'me'.
$3$. From $(B)$ and $(D)$,'jo' is common,and 'life' is common. So,'jo' = 'life'.
Statement $(C)$ ('tub od pit' = 'give me toy') provides information about 'give','toy',and 'od',which are not required to decode the core relationships between the other sentences. Thus,statement $(C)$ is redundant for the primary decoding process.

(D) $1$. Compare $(A)$ and $(B)$: The common code is 'zci' and the common word is 'good'. Thus,'zci' = 'good'.
$2$. Compare $(A)$ and $(D)$: The common code is 'das' and the common word is 'little'. Thus,'das' = 'little'.
$3$. From statement $(A)$,we have 'mxy das zci' = 'good little frock'.
$4$. Substituting the known codes: 'mxy' + 'little' + 'good' = 'good' + 'little' + 'frock'.
$5$. Therefore,'mxy' stands for 'frock'.

(C) To determine the code for each word,let us analyze the statements:
$1$. From $(A)$ and $(B)$,'zci' is common,and 'good' is common. So,'zci' = 'good'.
$2$. From $(A)$ and $(D)$,'das' is common,and 'little' is common. So,'das' = 'little'.
$3$. From $(B)$ and $(D)$,'cos' is common,and 'girl' is common. So,'cos' = 'girl'.
$4$. From $(A)$,'mxy' = 'frock'.
$5$. From $(B)$,'jmx' = 'behaves'.
$6$. From $(D)$,'ajp' = 'fell'.
$7$. Statement $(C)$ 'nvg drs cos' introduces new words 'makes' and 'mischief' which are not present in the other statements,and 'cos' (girl) is already identified. Since we can identify all words in the other statements without $(C)$,statement $(C)$ is superfluous.

(D) $1$. Compare $(A)$ 'pod najoe' ('very bright boy') and $(B)$ 'tam nu pod' ('the boy comes'). The common code is 'pod' and the common word is 'boy'. Thus,'pod' = 'boy'.
$2$. Compare $(A)$ 'pod najoe' ('very bright boy') and $(D)$ 'joc ton su' ('very good doll'). The common code is 'joc' (assuming 'najoe' is a typo for 'na joc' or similar,but based on common word 'very','joc' is common). Let's re-evaluate: In $(A)$ 'pod na joc' and $(D)$ 'joc ton su',the common word is 'very' and common code is 'joc'.
$3$. From $(A)$,'pod' = 'boy' and 'joc' = 'very'. Therefore,the remaining code 'na' must correspond to the remaining word 'bright'.
$4$. Thus,'bright' = 'na'.

(B) To determine the code for a specific word,we analyze the statements:
$1$. From $(A)$ and $(B)$,'pod' is common,and 'boy' is common. So,'pod' = 'boy'.
$2$. From $(B)$ and $(C)$,'nu' is common,and 'the' is common. So,'nu' = 'the'.
$3$. From $(C)$ and $(D)$,'ton' is common,and 'doll' is common. So,'ton' = 'doll'.
$4$. Since we can identify the codes for 'boy','the',and 'doll' using statements $(A)$,$(B)$,and $(C)$ or $(A)$,$(B)$,and $(D)$,statement $(C)$ is redundant if we have $(A), (B), (D)$ or vice versa. However,looking at the options provided and the logic of sufficiency,statement $(C)$ is the one that is not strictly necessary to derive the core relationships if other statements are present.

(A) $1$. Analyze the statements:
$(i)$ 'po ki top ma' = 'Usha is playing cards'
(ii) 'hop ja ki ma' = 'Asha is playing tennis'
(iii) 'ki top sop ho' = 'they are playing football'
(iv) 'po sur hop' = 'cards and tennis'
$2$. Compare $(i)$,(ii),and (iii):
Common words are 'is' and 'playing'. Common codes are 'ki' and 'ma'. Thus,'ki' and 'ma' represent 'is' and 'playing'.
$3$. Compare (ii) and (iv):
Common word is 'tennis'. Common code is 'hop'. Thus,'hop' = 'tennis'.
$4$. Analyze statement (ii) 'hop ja ki ma' = 'Asha is playing tennis':
We know 'hop' = 'tennis',and 'ki'/'ma' = 'is'/'playing'.
Remaining word is 'Asha' and remaining code is 'ja'.
Therefore,'ja' means 'Asha'.

(A) $1$. Compare statement $(B)$ 'Bis Tim Nak' ('Always seek knowledge') and statement $(C)$ 'Tim Terns Sik' ('Knowledge is truth'). The common code word is 'Tim' and the common word is 'knowledge'. Therefore,'Tim' = 'knowledge'.
$2$. Compare statement $(B)$ 'Bis Tim Nak' ('Always seek knowledge') and statement $(D)$ 'Lik Bis Zap' ('Never seek violence'). The common code word is 'Bis' and the common word is 'seek'. Therefore,'Bis' = 'seek'.
$3$. In statement $(B)$,we have 'Bis Tim Nak' representing 'Always seek knowledge'. Since 'Bis' = 'seek' and 'Tim' = 'knowledge',the remaining code 'Nak' must represent the remaining word 'Always'.
Thus,the code for 'Always' is 'Nak'.

(A) Let us analyze the codes:
$1$. From $(B)$ 'Bis Tim Nak' = 'Always seek knowledge' and $(C)$ 'Tim Terns Sik' = 'Knowledge is truth',we see that 'Tim' is common to both,and 'Knowledge' is common to both. So,'Tim' = 'Knowledge'.
$2$. From $(A)$ 'Kemp Lamp Terns' = 'Speak the truth' and $(C)$ 'Tim Terns Sik' = 'Knowledge is truth',we see that 'Terns' is common to both,and 'truth' is common to both. So,'Terns' = 'truth'.
$3$. From $(B)$ 'Bis Tim Nak' = 'Always seek knowledge' and $(D)$ 'Lik Bis Zap' = 'Never seek violence',we see that 'Bis' is common to both,and 'seek' is common to both. So,'Bis' = 'seek'.
$4$. Since we can derive the meanings of 'Tim','Terns',and 'Bis' using statements $(B)$,$(C)$,and $(D)$,statement $(A)$ is not necessary to decode the common words.

(D) $1$. Analyze the given codes:
'nee muk pic' = 'grave and concern' $(i)$
'ill dic so' = 'every body else' (ii)
'tur muk so' = 'body and soul' (iii)
$2$. Compare (ii) and (iii):
'ill dic so' and 'tur muk so' share the word 'so' and the word 'body'.
Therefore,'so' = 'body'.
$3$. From (ii),'ill' and 'dic' correspond to 'every' and 'else'.
Since there is no further information to distinguish between 'ill' and 'dic',the code for 'every' could be 'ill' or 'dic'.
$4$. From $(i)$,'muk' is common in $(i)$ and (iii),and 'and' is common in $(i)$ and (iii).
Therefore,'muk' = 'and'.
This leaves 'nee' and 'pic' for 'grave' and 'concern'.
$5$. Since we cannot definitively identify the code for 'every' ('ill' or 'dic') or 'concern' ('nee' or 'pic'),the combination 'every concern' cannot be determined.

(B) Let us analyze the given statements:
$1$. 'Ka Bi Pu Ya' = 'You are very intelligent'
$2$. 'Ya Lo Ka Wo' = 'They seem very intelligent'
$3$. 'La Pu Le' = 'You can see'
$4$. 'Sun Pun Yun Ya' = 'How intelligent she is'
Comparing $(1)$ and $(2)$: Common codes are '$Ka, Ya$' and common words are 'very,intelligent'. Thus,'$Ka, Ya$' correspond to 'very,intelligent'.
Comparing $(1)$ and $(3)$: Common code is '$Pu$' and common word is 'You'. Thus,'$Pu$' = 'You'.
From $(1)$,we have codes '$Ka, Bi, Pu, Ya$' for 'You,are,very,intelligent'.
Since '$Pu$' = 'You' and '$Ka, Ya$' = 'very,intelligent',the remaining code '$Bi$' must correspond to the remaining word 'are'.
Therefore,'$Bi$' means 'are'.

(C) $1$. Compare 'bir le nac' (green and tasty) and 'pic nac hor' (tomato is green). The common word is 'green' and the common code is 'nac'. So,'nac' = 'green'.
$2$. Compare 'pic nac hor' (tomato is green) and 'coc bir hor' (food is tasty). The common word is 'is' and the common code is 'hor'. So,'hor' = 'is'.
$3$. From 'pic nac hor',since 'nac' = 'green' and 'hor' = 'is',then 'pic' = 'tomato'.
$4$. Compare 'bir le nac' (green and tasty) and 'coc bir hor' (food is tasty). The common word is 'tasty' and the common code is 'bir'. So,'bir' = 'tasty'.
$5$. We need the code for 'tomato is tasty'. Based on our findings: 'tomato' = 'pic','is' = 'hor','tasty' = 'bir'.
$6$. Therefore,'tomato is tasty' is represented by 'pic hor bir' (or any order of these three codes).
$7$. Looking at the options,'pic hor bir' is not explicitly listed in the correct order,but option $C$ is 'hor bir pic',which contains the same three codes. Thus,'hor bir pic' is the correct representation.

(C) $1$. Analyze the statements:
$(i)$ 'kew xas huma deko' = 'she is eating apples'
(ii) 'kew tepo qua' = 'she sells toys'
(iii) 'sul lim deko' = '$I$ like apples'
$2$. Comparing $(i)$ and (ii),the common word is 'she' and the common code is 'kew'. Thus,'she' = 'kew'.
$3$. Comparing $(i)$ and (iii),the common word is 'apples' and the common code is 'deko'. Thus,'apples' = 'deko'.
$4$. Therefore,'she' corresponds to 'kew' and 'apples' corresponds to 'deko'.

(C) Let us analyze the given statements:
$1$) 'cinto baoli tsi mro' = 'her village is Sarurpur'
$2$) 'mhi cinto keepi tsi oind' = 'her first love is literature'
$3$) 'oind geit tsi cinto pki' = 'literature collection is her hobby'
Comparing $(1)$ and $(2)$:
Common codes: 'cinto','tsi'.
Common words: 'her','is'.
So,'cinto' and 'tsi' correspond to 'her' and 'is' (in any order).
Comparing $(2)$ and $(3)$:
Common codes: 'cinto','tsi','oind'.
Common words: 'her','is','literature'.
Since 'cinto' and 'tsi' are 'her' and 'is',the remaining code 'oind' must correspond to 'literature'.

(B) Analyze the given statements:
$1$. $4$ $il$ $be$ $pee$ $9$ = 'roses are blue'
$2$. $sik$ $hee$ $9$ = 'red flowers'
$3$. $pee$ $mit$ $hee$ $9$ = 'flowers are vegetables'
Comparing statement $2$ and statement $3$:
The common code words are $hee$ and $9$. The common word is 'flowers'. Thus,$hee$ $9$ stands for 'flowers'.
Now,looking at statement $2$ ($sik$ $hee$ $9$ = 'red flowers'):
Since $hee$ $9$ represents 'flowers',the remaining code $sik$ must represent 'red'.
Therefore,'red' is written as $sik$.

(D) $1$. Analyze the statements:
$(i)$ $il$ $be$ $pee$ = 'roses are blue'
(ii) $sik$ $hee$ = 'red flowers'
(iii) $pee$ $mit$ $hee$ = 'flowers are vegetables'
$2$. Compare (ii) and (iii):
Common word: 'flowers'
Common code: $hee$
So,$hee$ = 'flowers'.
$3$. From (iii),since $hee$ = 'flowers',the remaining codes are $pee$ and $mit$ for 'are' and 'vegetables'.
Comparing $(i)$ and (iii),the common word is 'are' and the common code is $pee$.
So,$pee$ = 'are'.
$4$. Now,substitute $pee$ = 'are' into $(i)$:
$il$ $be$ $pee$ = 'roses are blue'
$il$ $be$ = 'roses' and 'blue'.
$5$. Since we cannot distinguish between $il$ and $be$ for 'roses' and 'blue',the code for 'roses' cannot be determined.

(D) Step $1$: Analyze the given codes.
$1$) 'il be pee' = 'roses are blue'
$2$) 'sik hee' = 'red flowers'
$3$) 'pee mit hee' = 'flowers are vegetables'
Step $2$: Compare the statements to identify common words and codes.
Comparing $(2)$ and $(3)$: 'hee' is common in both codes,and 'flowers' is common in both meanings. Therefore,'hee' = 'flowers'.
From $(2)$,if 'hee' = 'flowers',then 'sik' = 'red'.
From $(3)$,'pee mit hee' = 'flowers are vegetables'. Since 'hee' = 'flowers','pee' and 'mit' represent 'are' and 'vegetables'.
Comparing $(1)$ and $(3)$: 'pee' is common in both,and 'are' is common in both meanings. Therefore,'pee' = 'are'.
Consequently,'mit' = 'vegetables'.
Step $3$: Translate 'vegetables are red flowers'.
'vegetables' = 'mit'
'are' = 'pee'
'red' = 'sik'
'flowers' = 'hee'
Thus,'vegetables are red flowers' is written as 'mit pee sik hee'.

(C) Analyze the given statements:
$1$) $786$ = 'study very hard'
$2$) $958$ = 'hard work pays'
$3$) $645$ = 'study and work'
Step $1$: Compare statement $1$ and $2$. The common word is 'hard' and the common digit is $8$. Therefore,'hard' = $8$.
Step $2$: Compare statement $1$ and $3$. The common word is 'study' and the common digit is $6$. Therefore,'study' = $6$.
Step $3$: From statement $1$,we have $786$ = 'study very hard'. Since 'study' = $6$ and 'hard' = $8$,the remaining digit $7$ must correspond to the remaining word 'very'.
Thus,'very' = $7$. The correct option is $C$.

(A) Step $1$: Analyze the statements to find common codes.
Statement $1$: '$324$' = 'Light is bright'
Statement $2$: '$629$' = 'Girl is beautiful'
Statement $3$: '$4758$' = '$I$ prefer bright clothes'
Step $2$: Compare Statement $1$ and Statement $2$.
The common word is 'is' and the common digit is $2$. Therefore,$2$ means 'is'.
Step $3$: Compare Statement $1$ and Statement $3$.
The common word is 'bright' and the common digit is $4$. Therefore,$4$ means 'bright'.
Step $4$: Determine the code for 'Light'.
In Statement $1$ ('$324$'),we have identified that $2$ = 'is' and $4$ = 'bright'.
Remaining digit $3$ must correspond to the remaining word 'Light'.
Thus,$3$ means 'Light'.
Correct option is $A$.

(D) Given:
$1$. '$37$' means 'which class'
$2$. '$583$' means 'caste and class'
Comparing the two statements,the common digit is '$3$' and the common word is 'class'. Therefore,'$3$' represents 'class'.
Now,in the second statement '$583$',since '$3$' is 'class',the remaining digits '$5$' and '$8$' represent 'caste' and 'and'.
Since we cannot distinguish between 'caste' and 'and' using the given information,the code for 'caste' must be either '$5$' or '$8$'.

(A) Analyze the given statements:
$1$. '$743$' = 'mangoes are good'
$2$. '$657$' = 'eat good food'
$3$. '$934$' = 'mangoes are ripe'
Comparing statement $1$ ('$743$') and statement $2$ ('$657$'),the common digit is $7$ and the common word is 'good'. Therefore,$7$ = 'good'.
Comparing statement $1$ ('$743$') and statement $3$ ('$934$'),the common digits are $4$ and $3$,and the common words are 'mangoes' and 'are'. Therefore,$4$ and $3$ represent 'mangoes' and 'are' (in any order).
Now,look at statement $3$ ('$934$'):
- We know $4$ and $3$ represent 'mangoes' and 'are'.
- The remaining digit is $9$ and the remaining word is 'ripe'.
Thus,the digit $9$ means 'ripe'.

(D) Analyze the given statements:
$1$. '$134$' means 'good and tasty'
$2$. '$478$' means 'see good pictures'
$3$. '$729$' means 'pictures are faint'
Step $1$: Compare statement $1$ and $2$. The common digit is $4$ and the common word is 'good'. Therefore,$4$ stands for 'good'.
Step $2$: Compare statement $2$ and $3$. The common digit is $7$ and the common word is 'pictures'. Therefore,$7$ stands for 'pictures'.
Step $3$: In statement $2$ ('$478$'),we know $4$ is 'good' and $7$ is 'pictures'. The remaining digit is $8$ and the remaining word is 'see'.
Thus,the digit $8$ stands for 'see'.

(C) Given statements:
$1$) $247$ = 'spread red carpet'
$2$) $256$ = 'dust one carpet'
$3$) $234$ = 'one red carpet'
Step $1$: Compare $(1)$ and $(3)$. The common words are 'red' and 'carpet',and the common digits are $2$ and $4$. Thus,'red' and 'carpet' correspond to $2$ and $4$ in some order.
Step $2$: Compare $(2)$ and $(3)$. The common word is 'one',and the common digit is $2$. Therefore,'one' = $2$.
Step $3$: Since 'one' = $2$,from Step $1$,'red' and 'carpet' must be $4$ and $7$ (from statement $1$) or $4$ and $3$ (from statement $3$). Looking at $(1)$ and $(3)$,'red' and 'carpet' are common,so they are $4$ and $2$ (wait,let's re-evaluate).
Correction:
- $(1)$ $247$: 'spread red carpet'
- $(2)$ $256$: 'dust one carpet'
- $(3)$ $234$: 'one red carpet'
Comparing $(2)$ and $(3)$: 'one' and 'carpet' are common. Digits $2$ and $6$ are in $(2)$,$2$ and $4$ are in $(3)$. Common digits are $2$. So 'one' or 'carpet' is $2$.
Comparing $(1)$ and $(3)$: 'red' and 'carpet' are common. Digits $2$ and $4$ are common. So 'red' and 'carpet' are $2$ and $4$.
Since 'red' and 'carpet' are $2$ and $4$,then in $(3)$ 'one' must be $3$.
In $(2)$,'one' is $3$,'carpet' is $2$ or $4$. If 'one' is $3$,then 'dust' must be $5$ or $6$. Since $2$ is 'carpet','dust' is $5$ or $6$. By elimination,'dust' is $5$.

(B) $1$. Analyze the given statements:
$(i)$ '$123$' = 'bright little boy'
(ii) '$145$' = 'tall big boy'
(iii) '$637$' = 'beautiful little flower'
$2$. Compare $(i)$ and (ii): The common digit is $1$ and the common word is 'boy'. Therefore,$1$ = 'boy'.
$3$. Compare $(i)$ and (iii): The common digit is $3$ and the common word is 'little'. Therefore,$3$ = 'little'.
$4$. In statement $(i)$,the remaining digit is $2$ and the remaining word is 'bright'. Therefore,$2$ = 'bright'.

(C) Given codes:
$1$) $256$ = 'you are good'
$2$) $637$ = 'we are bad'
$3$) $358$ = 'good and bad'
Step $1$: Compare $(1)$ and $(2)$. The common number is $6$ and the common word is 'are'. So,$6$ = 'are'.
Step $2$: Compare $(1)$ and $(3)$. The common number is $5$ and the common word is 'good'. So,$5$ = 'good'.
Step $3$: From $(1)$,since $6$ = 'are' and $5$ = 'good',the remaining number $2$ must represent 'you'.
Step $4$: Compare $(2)$ and $(3)$. The common number is $3$ and the common word is 'bad'. So,$3$ = 'bad'.
Step $5$: In $(3)$,we have 'good and bad' represented by $358$. We know $5$ = 'good' and $3$ = 'bad'. Therefore,the remaining number $8$ must represent 'and'.

(C) $1$. Analyze the statements:
- '$467$' = 'leaves are green'
- '$485$' = 'green is good'
- '$639$' = 'they are playing'
$2$. Compare '$467$' and '$485$': The common digit is $4$ and the common word is 'green'. Therefore,$4$ = 'green'.
$3$. Compare '$467$' and '$639$': The common digit is $6$ and the common word is 'are'. Therefore,$6$ = 'are'.
$4$. In the first statement '$467$' ('leaves are green'),we have identified $4$ = 'green' and $6$ = 'are'.
$5$. The remaining digit $7$ must correspond to the remaining word 'leaves'.
Thus,the digit $7$ stands for 'leaves'.

(B) Analyze the given statements:
$1$) $851$ = 'good sweet fruit'
$2$) $483$ = 'good red rose'
$3$) $341$ = 'rose and fruit'
Step $1$: Compare statement $(1)$ and $(2)$. The common digit is $8$ and the common word is 'good'. Therefore,$8$ stands for 'good'.
Step $2$: Compare statement $(1)$ and $(3)$. The common digit is $1$ and the common word is 'fruit'. Therefore,$1$ stands for 'fruit'.
Step $3$: In statement $(1)$,the remaining digit is $5$ and the remaining word is 'sweet'.
Thus,$5$ stands for 'sweet'.

(B) $1$. Analyze the statements:
- Statement $1$: '$479$' = 'fruit is sweet'
- Statement $2$: '$248$' = 'very sweet voice'
- Statement $3$: '$637$' = 'eat fruit daily'
$2$. Compare Statement $1$ and Statement $2$:
- The common word is 'sweet' and the common digit is $4$.
- Therefore,$4$ stands for 'sweet'.
$3$. Compare Statement $1$ and Statement $3$:
- The common word is 'fruit' and the common digit is $7$.
- Therefore,$7$ stands for 'fruit'.
$4$. Determine the code for 'is':
- In Statement $1$ ('$479$'),we know $4$ = 'sweet' and $7$ = 'fruit'.
- The remaining digit is $9$,which must correspond to the remaining word 'is'.
- Thus,$9$ stands for 'is'.

(D) $1$. Analyze the statements:
- '$123$' = 'hot filtered coffee'
- '$356$' = 'very hot day'
- '$589$' = 'day and night'
$2$. Compare the first and second statements:
- Common code digit: $3$
- Common word: 'hot'
- Therefore,$3$ stands for 'hot'.
$3$. Compare the second and third statements:
- Common code digit: $5$
- Common word: 'day'
- Therefore,$5$ stands for 'day'.
$4$. Analyze the second statement ('$356$' = 'very hot day'):
- We know $3$ = 'hot' and $5$ = 'day'.
- The remaining digit $6$ must stand for the remaining word 'very'.
- Thus,the digit $6$ stands for 'very'.

(B) $1$. Compare '$256$' ('red colour chalk') and '$245$' ('white colour chalk'). The common digits are '$2$' and '$5$',and the common words are 'colour' and 'chalk'.
$2$. Compare '$256$' ('red colour chalk') and '$589$' ('green colour flower'). The common digit is '$5$' and the common word is 'colour'. Therefore,'$5$' = 'colour'.
$3$. Since '$5$' = 'colour',from the comparison in step $1$,'$2$' must be 'chalk'.
$4$. Now,look at '$245$' ('white colour chalk'). We know '$5$' = 'colour' and '$2$' = 'chalk'. The remaining digit '$4$' must correspond to the remaining word 'white'.
$5$. Thus,the digit '$4$' means 'white'.

(C) Given statements:
$1$) '$526$' = 'sky is blue'
$2$) '$24$' = 'blue colour'
$3$) '$436$' = 'colour is fun'
Step $1$: Compare $(1)$ and $(2)$. The common code is '$2$' and the common word is 'blue'. So,'$2$' = 'blue'.
Step $2$: Compare $(2)$ and $(3)$. The common code is '$4$' and the common word is 'colour'. So,'$4$' = 'colour'.
Step $3$: From $(2)$,since '$2$' = 'blue' and '$4$' = 'colour',the remaining digit '$4$' in statement $(3)$ corresponds to 'colour'.
Step $4$: Compare $(1)$ and $(3)$. The common codes are '$6$' and '$3$' (from '$436$'). Since '$4$' is 'colour',the remaining digits in '$436$' are '$3$' and '$6$'. Comparing 'sky is blue' and 'colour is fun',the common word is 'is'. The common digits are '$6$'. So,'$6$' = 'is'.
Step $5$: In statement $(3)$ '$436$' = 'colour is fun',we have '$4$' = 'colour' and '$6$' = 'is'. Therefore,the remaining digit '$3$' must mean 'fun'.

(A) Analyze the given statements:
$1$. '$381$' = 'Hari is honest'
$2$. '$162$' = 'Shashi is intelligent'
$3$. '$948$' = 'Hari should go'
Step $1$: Compare statement $1$ and $2$.
The common digit is '$1$' and the common word is 'is'. Therefore,'$1$' means 'is'.
Step $2$: Compare statement $1$ and $3$.
The common digit is '$8$' and the common word is 'Hari'. Therefore,'$8$' means 'Hari'.
Step $3$: Determine the code for 'honest'.
In statement $1$ ('$381$'),we have identified that '$1$' is 'is' and '$8$' is 'Hari'.
This leaves the digit '$3$' for the word 'honest'.
Thus,'$3$' means 'honest'.

(A) Analyze the given statements:
$1$. '$253$' = 'books are old'
$2$. '$546$' = 'man is old'
$3$. '$378$' = 'buy good books'
Step $1$: Compare statement $1$ and $2$. The common digit is '$5$' and the common word is 'old'. Therefore,'$5$' stands for 'old'.
Step $2$: Compare statement $1$ and $3$. The common digit is '$3$' and the common word is 'books'. Therefore,'$3$' stands for 'books'.
Step $3$: In statement $1$ ('$253$'),we have identified '$5$' as 'old' and '$3$' as 'books'. The remaining digit is '$2$' and the remaining word is 'are'.
Thus,'$2$' stands for 'are'.

(C) Analyze the given statements:
$1$) $4975$ = 'Throw away garbage'
$2$) $528$ = 'Give away smoking'
$3$) $213$ = 'Smoking is harmful'
Step $1$: Compare statement $(1)$ and $(2)$. The common word is 'away' and the common digit is $5$. Therefore,$5$ = 'away'.
Step $2$: Compare statement $(2)$ and $(3)$. The common word is 'smoking' and the common digit is $2$. Therefore,$2$ = 'smoking'.
Step $3$: In statement $(2)$,we have $528$ = 'Give away smoking'. Since $5$ = 'away' and $2$ = 'smoking',the remaining digit $8$ must represent the remaining word 'Give'.
Thus,the digit $8$ means 'Give'.

(D) $1$. Analyze the statements:
- Statement $1$: $289$ = 'read from paper'
- Statement $2$: $276$ = 'tea from field'
- Statement $3$: $85$ = 'wall paper'
$2$. Compare Statement $1$ and Statement $2$:
- Common code digit: $2$
- Common word: 'from'
- Therefore,$2$ = 'from'.
$3$. Compare Statement $1$ and Statement $3$:
- Common code digit: $8$
- Common word: 'paper'
- Therefore,$8$ = 'paper'.
$4$. Analyze Statement $2$ ($276$ = 'tea from field'):
- We know $2$ = 'from'.
- Remaining codes are $7$ and $6$ for the words 'tea' and 'field'.
- Since we cannot distinguish between 'tea' and 'field',the code for 'tea' must be either $7$ or $6$.

(B) Given statements:
$1$) $289$ = 'read from paper'
$2$) $276$ = 'tea from field'
$3$) $85$ = 'wall paper'
Comparing statement $1$ and statement $2$:
The common digit is $2$ and the common word is 'from'. Therefore,$2$ = 'from'.
Comparing statement $1$ and statement $3$:
The common digit is $8$ and the common word is 'paper'. Therefore,$8$ = 'paper'.
Thus,the code for 'paper' is $8$.

(D) Step $1$: Analyze the given statements.
$(A)$ $134$ = 'you are well'
$(B)$ $758$ = 'they go home'
$(C)$ $839$ = 'we are home'
Step $2$: Compare statements $(B)$ and $(C)$.
Common word: 'home'.
Common digit: $8$.
So,'home' = $8$.
Step $3$: Analyze the remaining words in $(B)$.
In statement $(B)$,'they go' corresponds to the digits $7$ and $5$.
Since there is no further information to distinguish between 'they' and 'go',we cannot determine the specific code for 'they'.
Conclusion: The data is inadequate.

(A) To determine the code for 'home',we compare statements $(B)$ and $(C)$.
In $(B)$ '$758$' ('they go home') and $(C)$ '$839$' ('we are home'),the common word is 'home' and the common digit is '$8$'. Thus,'home' is '$8$'.
Statement $(A)$ '$134$' ('you are well') does not share any common words or digits with the other statements that would help in identifying the codes for 'they','go','we',or 'are'.
Since the question asks which statement can be dispensed with (is unnecessary) to answer the logic,statement $(A)$ is clearly redundant.

(B) $1$. Analyze the statements:
- $617$ = 'sweet and hot'
- $735$ = 'coffee is sweet'
- $263$ = 'tea is hot'
$2$. Compare the statements to find common codes:
- Comparing $617$ and $263$: The common digit is $6$ and the common word is 'hot'. Thus,$6$ = 'hot'.
- Comparing $617$ and $735$: The common digit is $7$ and the common word is 'sweet'. Thus,$7$ = 'sweet'.
- From $617$,since $6$ = 'hot' and $7$ = 'sweet',the remaining digit $1$ = 'and'.
- Comparing $735$ and $263$: The common digit is $3$ and the common word is 'is'. Thus,$3$ = 'is'.
- From $735$,since $7$ = 'sweet' and $3$ = 'is',the remaining digit $5$ = 'coffee'.
$3$. Determine the code for 'coffee is hot':
- 'coffee' = $5$
- 'is' = $3$
- 'hot' = $6$
- Therefore,'coffee is hot' is represented by $536$.

(D) Let the given statements be:
$1$) $3a, 2b, 7c$ = 'Truth is Eternal'
$2$) $7c, 9a, 8b, 3a$ = 'Enmity is not Eternal'
$3$) $9a, 4d, 2b, 8b$ = 'Truth does not perish'
Comparing $(1)$ and $(2)$,the common codes are $3a$ and $7c$,and the common words are 'is' and 'Eternal'. Thus,$3a$ and $7c$ represent 'is' and 'Eternal' in some order.
Comparing $(2)$ and $(3)$,the common code is $9a$ and $8b$,and the common word is 'not'. Wait,let's re-evaluate:
From $(2)$ and $(3)$,the common codes are $9a$ and $8b$,and the common word is 'not'. This implies 'not' is either $9a$ or $8b$.
Looking at $(2)$ again: $7c, 9a, 8b, 3a$ = 'Enmity is not Eternal'. Since $3a$ and $7c$ are 'is' and 'Eternal',the remaining codes $9a$ and $8b$ must represent 'Enmity' and 'not'.
From $(3)$,$9a, 4d, 2b, 8b$ = 'Truth does not perish'. Since $9a$ and $8b$ are 'not' and 'Enmity' (from statement $2$),and 'not' is common to $(2)$ and $(3)$,one of $9a$ or $8b$ must be 'not'.
Actually,comparing $(2)$ and $(3)$,the common codes are $9a$ and $8b$. The common word is 'not'.
In $(2)$,'Enmity' is the only word left after accounting for 'is','Eternal',and 'not'.
Since $9a$ and $8b$ are 'not' and 'Enmity',and 'not' is in $(3)$ while 'Enmity' is not,we look for the code unique to $(2)$. The code $8b$ is present in $(2)$ and $(3)$,so $8b$ must be 'not'. Therefore,$9a$ must be 'Enmity'.

(A) To determine the pattern,let us analyze the transformation from $FIVE$ to $GHWD$:
$F (+2) = H$
$I (-2) = G$
$V (+2) = X$ (Wait,let us re-examine the pattern: $F o G (+1)$,$I o H (-1)$,$V o W (+1)$,$E o D (-1)$).
Applying the same pattern $(+1, -1, +1, -1)$ to $HURT$:
$H + 1 = I$
$U - 1 = T$
$R + 1 = S$
$T - 1 = S$
Thus,$HURT$ is written as $ITSS$.

(D) Given codes:
$1$) 'La Ke Ta' = 'go and swim'
$2$) 'Ne La Se' = 'you swim here'
$3$) 'Pe Ke Ne Ta' = 'he and you go'
Step $1$: Compare $(1)$ and $(2)$. The common word is 'swim' and the common code is 'La'. So,'La' = 'swim'.
Step $2$: Compare $(1)$ and $(3)$. The common words are 'go' and 'and'. The common codes are 'Ke' and 'Ta'. So,'Ke'/'Ta' = 'go'/'and'.
Step $3$: From $(2)$,we have 'Ne La Se' = 'you swim here'. Since 'La' = 'swim',the remaining codes 'Ne' and 'Se' correspond to 'you' and 'here'.
Step $4$: From $(3)$,we have 'Pe Ke Ne Ta' = 'he and you go'. We know 'Ke' and 'Ta' are 'go' and 'and'. Thus,'Pe' and 'Ne' correspond to 'he' and 'you'.
Step $5$: Since 'Ne' is common in $(2)$ and $(3)$,and 'you' is the common word,'Ne' = 'you'.
Step $6$: Returning to $(2)$,if 'Ne' = 'you' and 'La' = 'swim',then the remaining code 'Se' must be 'here'.

(B) Given codes are:
$ROBE = 5136$
$BIND = 3792$
By comparing the letters and their corresponding digits:
$R = 5, O = 1, B = 3, E = 6$
$B = 3, I = 7, N = 9, D = 2$
We need to find the code for $RIDE$:
$R = 5$
$I = 7$
$D = 2$
$E = 6$
Therefore,$RIDE$ is written as $5726$.

(B) We cut fruit with a knife.
According to the given information,'knife' is called 'jug'.
Therefore,we use a 'jug' to cut fruit.

(B) The substitution follows a reverse alphabetical order where '$A=26$', '$B=25$', ..., '$Z=1$'.
This can be calculated using the formula: $\text{Value} = 27 - (\text{Position of letter in English alphabet})$.
For the word '$WAXY$':
$W$: Position is $23$, so value $= 27 - 23 = 4$.
$A$: Position is $1$, so value $= 27 - 1 = 26$.
$X$: Position is $24$, so value $= 27 - 24 = 3$.
$Y$: Position is $25$, so value $= 27 - 25 = 2$.
Sum $= 4 + 26 + 3 + 2 = 35$.

Solution:
Given codes:
$BOARD = 54\#12$
$MORE = 941\$$
Mapping the letters:
$B = 5$
$O = 4$
$A = \#$
$R = 1$
$D = 2$
$M = 9$
$E = \$$
Now, for $DREAM$:
$D = 2$, $R = 1$, $E = \$$, $A = \#$, $M = 9$
Thus,
$DREAM = 21\$\#9$

(B) Given the coding scheme:
$D = Q$
$A = M$
$N = Z$
$G = T$
$E = V$
$R = I$
To find the code for the word $DANGER$,we substitute each letter with its corresponding code:
$D \rightarrow Q$
$A \rightarrow M$
$N \rightarrow Z$
$G \rightarrow T$
$E \rightarrow V$
$R \rightarrow I$
Combining these,we get $QMZTVI$.
Therefore,the correct option is $B$.

(A) To find the sum of the numbers substituted for the word $DECAY$,we first assign the numerical value to each letter based on its position in the English alphabet:
$D = 4$
$E = 5$
$C = 3$
$A = 1$
$Y = 25$
Now,calculate the sum of these values:
$Sum = 4 + 5 + 3 + 1 + 25 = 38$
Therefore,the sum of the numbers substituted for the word $DECAY$ is $38$.