Coding-Decoding Questions in English

(D) Clearly,each letter in the code is the alphabet immediately preceding the corresponding letter in the word.
$T - 1 = S$
$A - 1 = Z$
$P - 1 = O$
Thus,for $FREEZE$:
$F - 1 = E$
$R - 1 = Q$
$E - 1 = D$
$E - 1 = D$
$Z - 1 = Y$
$E - 1 = D$
Therefore,$FREEZE$ is coded as $EQDDYD$. The correct option is $D$.

(B) Analyze the pattern in the word $GAMBLE$ coded as $FBLCKF$:
$G$ (position $1$,odd) $\rightarrow$ $G-1 = F$
$A$ (position $2$,even) $\rightarrow$ $A+1 = B$
$M$ (position $3$,odd) $\rightarrow$ $M-1 = L$
$B$ (position $4$,even) $\rightarrow$ $B+1 = C$
$L$ (position $5$,odd) $\rightarrow$ $L-1 = K$
$E$ (position $6$,even) $\rightarrow$ $E+1 = F$
Thus,odd positions are shifted by $-1$ and even positions are shifted by $+1$.
Applying this to $FLOWER$:
$F$ ($1$,odd) $\rightarrow$ $F-1 = E$
$L$ ($2$,even) $\rightarrow$ $L+1 = M$
$O$ ($3$,odd) $\rightarrow$ $O-1 = N$
$W$ ($4$,even) $\rightarrow$ $W+1 = X$
$E$ ($5$,odd) $\rightarrow$ $E-1 = D$
$R$ ($6$,even) $\rightarrow$ $R+1 = S$
Result: $EMNXDS$.

(B) Analyze the pattern of the word $PENSION$ ($7$ letters) coded as $NEISNOP$:
$P$ (1st) and $N$ (7th) are swapped.
$E$ (2nd) and $O$ (6th) are swapped.
$N$ (3rd) and $P$ (5th) are swapped.
$S$ (4th) remains in the middle.
Wait,let's re-examine the mapping: $P-E-N-S-I-O-N \rightarrow N-E-I-S-N-O-P$.
Positions: $1-2-3-4-5-6-7 \rightarrow 7-2-5-4-3-6-1$.
Applying this to $FOLIAGE$ $(1-2-3-4-5-6-7)$:
$F(1), O(2), L(3), I(4), A(5), G(6), E(7)$.
Following the pattern $7-2-5-4-3-6-1$:
$7: E, 2: O, 5: A, 4: I, 3: L, 6: G, 1: F$.
Result: $EOAILGF$. Thus,the correct option is $B$.

(A) To find the code,we observe the pattern between the letters of $PLANE$ and $OKZMD$:
$P - 1 = O$
$L - 1 = K$
$A - 1 = Z$
$N - 1 = M$
$E - 1 = D$
Each letter in the word is replaced by the letter immediately preceding it in the English alphabet.
Applying the same logic to $TRAIN$:
$T - 1 = S$
$R - 1 = Q$
$A - 1 = Z$
$I - 1 = H$
$N - 1 = M$
Therefore,$TRAIN$ is coded as $SQZHM$.

(C) Analyze the pattern between $SPACE$ and $TQBDF$:
$S + 1 = T$
$P + 1 = Q$
$A + 1 = B$
$C + 1 = D$
$E + 1 = F$
Each letter is shifted by $+1$ in the alphabetical order.
Applying the same logic to $PURSE$:
$P + 1 = Q$
$U + 1 = V$
$R + 1 = S$
$S + 1 = T$
$E + 1 = F$
Thus,$PURSE$ is coded as $QVSTF$.

(D) Analyze the pattern in $NATURE$ to $MASUQE$:
$N$ (1st,odd) $\rightarrow$ $M$ (previous letter)
$A$ (2nd,even) $\rightarrow$ $A$ (same)
$T$ (3rd,odd) $\rightarrow$ $S$ (previous letter)
$U$ (4th,even) $\rightarrow$ $U$ (same)
$R$ (5th,odd) $\rightarrow$ $Q$ (previous letter)
$E$ (6th,even) $\rightarrow$ $E$ (same)
Applying this logic to $FAMINE$:
$F$ (1st,odd) $\rightarrow$ $E$ (previous letter)
$A$ (2nd,even) $\rightarrow$ $A$ (same)
$M$ (3rd,odd) $\rightarrow$ $L$ (previous letter)
$I$ (4th,even) $\rightarrow$ $I$ (same)
$N$ (5th,odd) $\rightarrow$ $M$ (previous letter)
$E$ (6th,even) $\rightarrow$ $E$ (same)
Thus,$FAMINE$ is coded as $EALIME$.

(C) In the given code,the word $SECURE$ is reversed to form $ERUCES$.
Following the same logic,the word $SALINE$ is reversed to form $ENILAS$.

(B) The word $MECHANICS$ has $9$ letters. The code $HCEMASCIN$ is formed by reversing the first $4$ letters ($MECH$ becomes $HCEM$) and the last $4$ letters ($NICS$ becomes $SCIN$),while the middle letter $A$ remains in its position.
Applying the same logic to $POSTER$ ($6$ letters):
Since there is no middle letter,we split the word into two halves of $3$ letters each: $POS$ and $TER$.
Reversing $POS$ gives $SOP$.
Reversing $TER$ gives $RET$.
Combining these,the code for $POSTER$ is $SOPRET$.

(A) In the given code,every two letters are reversed in their order.
For the word $DISPEL$:
$DI$ becomes $ID$,$SP$ becomes $PS$,and $EL$ becomes $LE$.
Thus,$DISPEL$ is coded as $IDPSLE$.
Applying the same logic to the word $EFFECT$:
$EF$ becomes $FE$,$FE$ becomes $EF$,and $CT$ becomes $TC$.
Therefore,$EFFECT$ is coded as $FEEFTC$.

(B) The pattern for coding is as follows:
For the word $BATCH$:
$B$ (1st position,odd) $\rightarrow$ $B-1 = A$
$A$ (2nd position,even) $\rightarrow$ $A+1 = B$
$T$ (3rd position,odd) $\rightarrow$ $T-1 = S$
$C$ (4th position,even) $\rightarrow$ $C+1 = D$
$H$ (5th position,odd) $\rightarrow$ $H-1 = G$
Thus,$BATCH$ is coded as $ABSDG$.
Applying the same logic to $FORSAKE$:
$F$ (1st,odd) $\rightarrow$ $F-1 = E$
$O$ (2nd,even) $\rightarrow$ $O+1 = P$
$R$ (3rd,odd) $\rightarrow$ $R-1 = Q$
$S$ (4th,even) $\rightarrow$ $S+1 = T$
$A$ (5th,odd) $\rightarrow$ $A-1 = Z$
$K$ (6th,even) $\rightarrow$ $K+1 = L$
$E$ (7th,odd) $\rightarrow$ $E-1 = D$
Result: $EPQTZLD$.

(B) In the given code,the letters at odd positions are shifted one alphabet ahead $(+1)$,and the letters at even positions are shifted one alphabet behind $(-1)$.
For $GOODNESS$:
$G(+1)=H, O(-1)=N, O(+1)=P, D(-1)=C, N(+1)=O, E(-1)=D, S(+1)=T, S(-1)=R$.
Result: $HNPCODTR$.
Applying the same logic to $GREATNESS$:
$G(+1)=H$
$R(-1)=Q$
$E(+1)=F$
$A(-1)=Z$
$T(+1)=U$
$N(-1)=M$
$E(+1)=F$
$S(-1)=R$
$S(+1)=T$
Therefore,$GREATNESS$ is coded as $HQFZUMFRT$.

(C) The pattern for coding is as follows:
$F (-1) = E$
$O (+2) = Q$
$U (-3) = R$
$G (+4) = K$
$H (-5) = C$
$T (+6) = Z$
Applying the same pattern to $MALE$:
$M (-1) = L$
$A (+2) = C$
$L (-3) = I$
$E (+4) = I$
Therefore,$MALE$ is coded as $LCII$.

(B) Analyze the pattern in $BLEMISH$ $\rightarrow$ $AODPHVG$:
$B$ (2nd letter) $\rightarrow$ $A$ (-$1$)
$L$ (12th letter) $\rightarrow$ $O$ (+$3$)
$E$ (5th letter) $\rightarrow$ $D$ (-$1$)
$M$ (13th letter) $\rightarrow$ $P$ (+$3$)
$I$ (9th letter) $\rightarrow$ $H$ (-$1$)
$S$ (19th letter) $\rightarrow$ $V$ (+$3$)
$H$ (8th letter) $\rightarrow$ $G$ (-$1$)
Pattern: Odd positions are $-1$,Even positions are $+3$.
Applying this to $CHAPTER$:
$C$ (1st) $-1 = B$
$H$ (2nd) $+3 = K$
$A$ (3rd) $-1 = Z$
$P$ (4th) $+3 = S$
$T$ (5th) $-1 = S$
$E$ (6th) $+3 = H$
$R$ (7th) $-1 = Q$
Result: $BKZSSHQ$.

(D) The pattern for coding $ALMIRAH$ to $BNPMWGO$ is as follows:
$A (+1) = B$
$L (+2) = N$
$M (+3) = P$
$I (+4) = M$
$R (+5) = W$
$A (+6) = G$
$H (+7) = O$
To find the original word for $DNRWLUA$,we reverse the process by subtracting the positions:
$D (-1) = C$
$N (-2) = L$
$R (-3) = O$
$W (-4) = S$
$L (-5) = G$
$U (-6) = O$
$A (-7) = T$
Thus,the word is $CLOSGOT$.

(C) The pattern for coding $SWITCH$ to $TVJSDG$ is as follows:
$S (+1) = T$
$W (-1) = V$
$I (+1) = J$
$T (-1) = S$
$C (+1) = D$
$H (-1) = G$
Thus,the pattern is $+1, -1, +1, -1, +1, -1$.
To find the word for $CQFZE$,we reverse the operations:
$C (-1) = B$
$Q (+1) = R$
$F (-1) = E$
$Z (+1) = A$
$E (-1) = D$
The resulting word is $BREAD$. Therefore,the correct option is $C$.

(C) The given code $ROTAREGIRFER$ is the reverse of the word $REFRIGERATOR$.
To find the original word for the code $NOITINUMMA$,we need to reverse the letters of the given code.
Reversing $NOITINUMMA$ gives $AMMUNITION$.
Therefore,the correct word is $AMMUNITION$,which corresponds to option $C$.

(D) In the given code,each letter of the word $UTENSIL$ is shifted forward by $2$ positions to obtain the code $WVGPUKN$ $(U+2=W, T+2=V, E+2=G, N+2=P, S+2=U, I+2=K, L+2=N)$.
To find the word for the code $DMSFXG$,we must shift each letter backward by $2$ positions:
$D - 2 = B$
$M - 2 = K$
$S - 2 = Q$
$F - 2 = D$
$X - 2 = V$
$G - 2 = E$
Thus,the word is $BKQDVE$.

(D) In the word $REMOTE$,the letters are at positions $1, 2, 3, 4, 5, 6$.
The code $ROTEME$ is formed by keeping the $1^{st}$ and $6^{th}$ letters fixed and swapping the $2^{nd}$ with $3^{rd}$ and $4^{th}$ with $5^{th}$ letters.
Applying this logic to $PNIICC$ $(1=P, 2=N, 3=I, 4=I, 5=C, 6=C)$:
Keep $1^{st}$ $(P)$ and $6^{th}$ $(C)$ fixed.
Swap $2^{nd}$ $(N)$ and $3^{rd}$ $(I)$ $\rightarrow$ $IN$.
Swap $4^{th}$ $(I)$ and $5^{th}$ $(C)$ $\rightarrow$ $CI$.
Combining these,we get $P + IN + CI + C = PICNIC$.

(A) To find the pattern,compare $SHIFT$ with $RFFBO$:
$S - 1 = R$
$H - 2 = F$
$I - 3 = F$
$F - 4 = B$
$T - 5 = O$
Thus,the code is obtained by subtracting $1, 2, 3, 4, 5$ from the positions of the letters.
To find the word for $LKUMB$,we reverse the process by adding $1, 2, 3, 4, 5$:
$L + 1 = M$
$K + 2 = M$
$U + 3 = X$
$M + 4 = Q$
$B + 5 = G$
Therefore,the word is $MMXQG$.

(A) To find the pattern,compare the letters of $TRIANGLE$ and $SQHZMFKD$:
$T(-1) = S$
$R(-1) = Q$
$I(-1) = H$
$A(-1) = Z$
$N(-1) = M$
$G(-1) = F$
$L(-1) = K$
$E(-1) = D$
The pattern is that each letter in the word is shifted one position backward in the alphabet to get the code.
To find the word for $DWZLOKD$,we shift each letter one position forward:
$D(+1) = E$
$W(+1) = X$
$Z(+1) = A$
$L(+1) = M$
$O(+1) = P$
$K(+1) = L$
$D(+1) = E$
Thus,the word is $EXAMPLE$.

(B) To find the pattern, compare the letters of $GRASP$ with $BMVNK$:
$G (7) - 5 = B (2)$
$R (18) - 5 = M (13)$
$A (1) - 5 = V (22)$ (cycling backwards through the alphabet)
$S (19) - 5 = N (14)$
$P (16) - 5 = K (11)$
Each letter in the code is $5$ positions behind the original word.
To find the word for $CRANE$, we must move $5$ positions forward for each letter:
$C (3) + 5 = H (8)$
$R (18) + 5 = W (23)$
$A (1) + 5 = F (6)$
$N (14) + 5 = S (19)$
$E (5) + 5 = J (10)$
Thus, the word is $HWFSJ$.

(B) The pattern for coding $MACHINE$ as $LBBIHOD$ is as follows:
$M - 1 = L$
$A + 1 = B$
$C - 1 = B$
$H - 1 = I$ (Wait,let's re-evaluate: $M(-1)=L, A(+1)=B, C(-1)=B, H(+1)=I, I(-1)=H, N(+1)=O, E(-1)=D$)
The pattern is $-1, +1, -1, +1, -1, +1, -1$.
To find the word for $SLTMFNB$,we reverse the operations $(+1, -1, +1, -1, +1, -1, +1)$:
$S + 1 = T$
$L - 1 = K$
$T + 1 = U$
$M - 1 = L$
$F + 1 = G$
$N - 1 = M$
$B + 1 = C$
Thus,the word is $TKULGMC$.

(B) Analyze the pattern of the code $PORCELAIN \rightarrow QOSCFLBJO$:
$P+1=Q$,$O=O$,$R+1=S$,$C=C$,$E+1=F$,$L=L$,$A+1=B$,$I+1=J$,$N+1=O$.
Wait,let us re-examine the pattern: $P(16) ightarrow Q(17) (+1)$,$O(15) ightarrow O(15) (0)$,$R(18) ightarrow S(19) (+1)$,$C(3) ightarrow C(3) (0)$,$E(5) ightarrow F(6) (+1)$,$L(12) ightarrow L(12) (0)$,$A(1) ightarrow B(2) (+1)$,$I(9) ightarrow J(10) (+1)$,$N(14) ightarrow O(15) (+1)$.
Actually,the pattern is: odd positions $+1$,even positions $0$.
Applying this to find the word for $BKMOUSPP$:
$B-1=A$,$K=K$,$M-1=L$,$O=O$,$U-1=T$,$S=S$,$P-1=O$,$P-1=O$ (Wait,the last two letters $PP$ suggest a different pattern).
Let us re-evaluate: $P(16) ightarrow Q(17)$,$O(15) ightarrow O(15)$,$R(18) ightarrow S(19)$,$C(3) ightarrow C(3)$,$E(5) ightarrow F(6)$,$L(12) ightarrow L(12)$,$A(1) ightarrow B(2)$,$I(9) ightarrow J(10)$,$N(14) ightarrow O(15)$.
For $BKMOUSPP$: $B-1=A$,$K=K$,$M-1=L$,$O=O$,$U-1=T$,$S=S$,$P-1=O$,$P-1=O$ is not correct. If we reverse the logic: $B-1=A$,$K=K$,$M-1=L$,$O=O$,$U-1=T$,$S=R$,$P-1=O$,$P-1=O$. The correct word is $ALLOTROPY$.

(D) The word $BLEACH$ is divided into pairs: $(BL), (EA), (CH)$.
Reversing the letters in each pair gives: $(LB), (AE), (HC)$.
Combining these,we get the code $LBAEHC$.
Applying the same logic to the code $NBOLZKMH$,we divide it into pairs: $(NB), (OL), (ZK), (MH)$.
Reversing the letters in each pair gives: $(BN), (LO), (KZ), (HM)$.
Combining these,we get the original word: $BNLOKZHM$.

(B) In the given code $POPULAR \rightarrow QPQVMBS$,each letter is shifted by $+1$ position in the alphabet $(P+1=Q, O+1=P, P+1=Q, U+1=V, L+1=M, A+1=B, R+1=S)$.
To find the word for the code $GBNPVT$,we need to shift each letter by $-1$ position:
$G-1 = F$
$B-1 = A$
$N-1 = M$
$P-1 = O$
$V-1 = U$
$T-1 = S$
Therefore,the word is $FAMOUS$.

(B) To find the pattern,compare the letters of $CRICKET$ and $FULFNHW$:
$C (+3) = F$
$R (+3) = U$
$I (+3) = L$
$C (+3) = F$
$K (+3) = N$
$E (+3) = H$
$T (+3) = W$
The pattern is that each letter is shifted forward by $3$ positions.
To find the original word for the code $EULGH$,we must shift each letter backward by $3$ positions:
$E (-3) = B$
$U (-3) = R$
$L (-3) = I$
$G (-3) = D$
$H (-3) = E$
Therefore,the word is $BRIDE$.

(A) By observing the given codes,we can map each letter to its corresponding digit:
$S = 5, I = 3, T = 5, E = 0, R = 1$
$U = 8, N = 4, C = 6, L = 7, E = 0$
$B = 1, O = 2, Y = 9$
Now,we need to find the code for $SON$:
$S = 5$
$O = 2$
$N = 4$
Thus,$SON$ is coded as $524$.

(C) The alphabets are coded as follows:
$G = 5, I = 1, V = 3, E = 7$
$B = 9, A = 2, T = 4$
To find the code for $GATE$,we map the letters to their respective numbers:
$G = 5$
$A = 2$
$T = 4$
$E = 7$
Therefore,$GATE$ is coded as $5247$.
The correct option is $C$.

(B) By comparing the given codes,we can assign a specific digit to each letter:
$P = 2$
$A = 1$
$L = 3$
$E = 4$
$R = 5$
$T = 9$
$H = 0$
Now,we map the letters of the word $PEARL$ to their respective digits:
$P = 2$
$E = 4$
$A = 1$
$R = 5$
$L = 3$
Therefore,$PEARL$ is coded as $24153$.

(C) By comparing the given codes:
$RIPPLE = 613382$
$LIFE = 8192$
From these,we can map the letters to their respective digits:
$R = 6, I = 1, P = 3, L = 8, E = 2$
From $LIFE = 8192$,we have $L=8, I=1, F=9, E=2$.
Now,for $RIFFLE$:
$R = 6$
$I = 1$
$F = 9$
$F = 9$
$L = 8$
$E = 2$
Therefore,$RIFFLE$ is coded as $619982$.

(B) By comparing the given words and their codes,we can identify the digit assigned to each letter:
$R = 6, O = 8, S = 2, E = 1$
$C = 7, H = 3, A = 4, I = 5$
$P = 9$
Now,for the word $SEARCH$:
$S = 2$
$E = 1$
$A = 4$
$R = 6$
$C = 7$
$H = 3$
Therefore,the code for $SEARCH$ is $214673$.

(A) By comparing the given codes,we can identify the digit assigned to each letter:
$T = 8, W = 6, E = 3, N = 9, T = 8, Y = 5$ (for $TWENTY = 863985$)
$E = 3, L = 2, E = 3, V = 0, E = 3, N = 9$ (for $ELEVEN = 323039$)
Mapping the letters to their respective digits:
$T = 8, W = 6, E = 3, L = 2, V = 0, E = 3$
Therefore,$TWELVE$ is written as $863203$.

(C) The alphabets are assigned numerical values based on their position in the English alphabet $(A=1, B=2, C=3, \dots, Z=26)$.
For the word $HIGH$:
$H$ is the $8^{th}$ letter,so $H = 8$.
$I$ is the $9^{th}$ letter,so $I = 9$.
$G$ is the $7^{th}$ letter,so $G = 7$.
$H$ is the $8^{th}$ letter,so $H = 8$.
Combining these values,the code for $HIGH$ is $8978$.

(B) From the given codes:
$ENTRY = 12345$ implies $E=1, N=2, T=3, R=4, Y=5$.
$STEADY = 931785$ implies $S=9, T=3, E=1, A=7, D=8, Y=5$.
Comparing both,we get the mapping: $E=1, N=2, T=3, R=4, Y=5, S=9, A=7, D=8$.
Now,for the word $NEATNESS$:
$N = 2$
$E = 1$
$A = 7$
$T = 3$
$N = 2$
$E = 1$
$S = 9$
$S = 9$
Therefore,the code for $NEATNESS$ is $21732199$.

(B) The alphabets in the words are coded as follows:
$ENTRY \rightarrow 12345$
$STEADY \rightarrow 931785$
By comparing the letters:
$E=1, N=2, T=3, R=4, Y=5$
$S=9, T=3, E=1, A=7, D=8$
Now,for the word $ARREST$:
$A = 7$
$R = 4$
$R = 4$
$E = 1$
$S = 9$
$T = 3$
Therefore,the code for $ARREST$ is $744193$.

(C) The alphabets in the words are coded as follows:
$ENTRY \rightarrow 12345$
$STEADY \rightarrow 931785$
By comparing the letters:
$E=1, N=2, T=3, R=4, Y=5$
$S=9, T=3, E=1, A=7, D=8, Y=5$
Mapping for $ENDEAR$:
$E=1$
$N=2$
$D=8$
$E=1$
$A=7$
$R=4$
Therefore,the code for $ENDEAR$ is $128174$.

(B) The alphabets in the words are coded as follows:
$C = 4, H = 5, A = 1, R = 6, C = 4, O = 9, A = 1, L = 3$
$M = 2, O = 9, R = 6, A = 1, L = 3, E = 7$
By comparing the letters in $REAL$ with the given codes:
$R = 6$
$E = 7$
$A = 1$
$L = 3$
Therefore,the code for $REAL$ is $6713$.

(A) By analyzing the given codes:
$CHARCOAL = 45164913$
$MORALE = 296137$
Mapping the letters to their respective digits:
$C = 4, H = 5, A = 1, R = 6, O = 9, L = 3, M = 2, E = 7$
Now,for the word $COACH$:
$C = 4$
$O = 9$
$A = 1$
$C = 4$
$H = 5$
Therefore,the code for $COACH$ is $49145$.

(D) By observing the given codes,we can map each letter to its corresponding digit:
$C = 4$
$H = 5$
$A = 1$
$R = 6$
$O = 9$
$L = 3$
$M = 2$
$E = 7$
Now,for the word $COLLAR$,we substitute the letters with their respective codes:
$C = 4$
$O = 9$
$L = 3$
$L = 3$
$A = 1$
$R = 6$
Therefore,the code for $COLLAR$ is $493316$.

(A) The alphabets in the words are coded as follows:
$M = 9, I = 7, S = 6, T = 5, A = 4, K = 1, E = 2, N = 8, D = 3$.
By mapping these values to the word $DISTANT$:
$D = 3$
$I = 7$
$S = 6$
$T = 5$
$A = 4$
$N = 8$
$T = 5$
Therefore,the code for $DISTANT$ is $3765485$.

(B) By comparing the letters in the given words,we can identify the code for each letter:
$M = 9, I = 7, S = 6, T = 5, A = 4, K = 1, E = 2$
From $NAKED = 84123$,we have $N = 8, A = 4, K = 1, E = 2, D = 3$.
Now,we map the letters of $ASSIST$ using these codes:
$A = 4$
$S = 6$
$S = 6$
$I = 7$
$S = 6$
$T = 5$
Therefore,the code for $ASSIST$ is $466765$.

(C) The alphabets in the words are coded as follows:
$M = 9, I = 7, S = 6, T = 5, A = 4, K = 1, E = 2$
$N = 8, A = 4, K = 1, E = 2, D = 3$
By comparing both codes,we get the mapping:
$I = 7, N = 8, T = 5, I = 7, M = 9, A = 4, T = 5, E = 2$
Therefore,the code for $INTIMATE$ is $78579452$.

(D) The alphabets in the words are coded as follows:
$M = 9, I = 7, S = 6, T = 5, A = 4, K = 1, E = 2$
$N = 8, A = 4, K = 1, E = 2, D = 3$
By comparing the letters,we get the following mapping:
$S = 6, T = 5, A = 4, I = 7, N = 8$
Therefore,the code for $STAIN$ is $65478$.

(B) The letters in the words are assigned specific numerical codes based on their positions in the given strings:
For $ROPE$: $R=6, O=8, P=2, E=1$.
For $CHAIR$: $C=7, H=3, A=4, I=5, R=6$.
To find the code for $CRAPE$,we map each letter to its corresponding digit:
$C = 7$
$R = 6$
$A = 4$
$P = 2$
$E = 1$
Therefore,the code for $CRAPE$ is $76421$.

(A) The alphabets are coded as follows:
$P=8, L=1, A=2, Y=3$
$R=4, H=9, Y=3, M=6, E=7$
To find the code for $MALE$,we map the letters to their respective numbers:
$M=6$
$A=2$
$L=1$
$E=7$
Therefore,$MALE$ is coded as $6217$.

(B) By comparing the given codes:
$PRIVATE = 1234567$
$RIST = 2396$
From $PRIVATE$,we have: $P=1, R=2, I=3, V=4, A=5, T=6, E=7$.
From $RIST$,we have: $R=2, I=3, S=9, T=6$.
Combining these,we identify the code for each letter: $R=2, I=3, V=4, E=7, T=6, S=9$.
Therefore,$RIVETS$ is coded as $234769$.

(A) To find the pattern,let us analyze the transformation of each digit:
Position $1$ (odd): $2 + 1 = 3$
Position $2$ (even): $4 - 1 = 3$
Position $3$ (odd): $6 + 1 = 7$
Position $4$ (even): $8 - 1 = 7$
Position $5$ (odd): $5 + 1 = 6$
The pattern is: add $1$ to digits at odd positions and subtract $1$ from digits at even positions.
Applying this to $35791$:
Position $1$ (odd): $3 + 1 = 4$
Position $2$ (even): $5 - 1 = 4$
Position $3$ (odd): $7 + 1 = 8$
Position $4$ (even): $9 - 1 = 8$
Position $5$ (odd): $1 + 1 = 2$
Thus,$35791$ is written as $44882$.

(B) To find the pattern,compare the digits of $35796$ and $44887$:
$3 + 1 = 4$
$5 - 1 = 4$
$7 + 1 = 8$
$9 - 1 = 8$
$6 + 1 = 7$
The pattern is $+1, -1, +1, -1, +1$.
Applying this pattern to $46823$:
$4 + 1 = 5$
$6 - 1 = 5$
$8 + 1 = 9$
$2 - 1 = 1$
$3 + 1 = 4$
Thus,$46823$ is written as $55914$.

(B) Clearly,each letter in the word $MYSTIFY$ is moved one step forward in the alphabetical order to obtain the corresponding letter of the code.
$M \rightarrow N$
$Y \rightarrow Z$
$S \rightarrow T$
$T \rightarrow U$
$I \rightarrow J$
$F \rightarrow G$
$Y \rightarrow Z$
Following the same pattern for $NEMESIS$:
$N \rightarrow O$
$E \rightarrow F$
$M \rightarrow N$
$E \rightarrow F$
$S \rightarrow T$
$I \rightarrow J$
$S \rightarrow T$
Thus,the code for $NEMESIS$ becomes $OFNFTJT$.
Hence,the correct option is $B$.

(D) Clearly,each letter in the word $TAP$ is moved one step backward in the alphabet to obtain the corresponding letter of the code.
$T - 1 = S$
$A - 1 = Z$
$P - 1 = O$
Applying the same logic to $FREEZE$:
$F - 1 = E$
$R - 1 = Q$
$E - 1 = D$
$E - 1 = D$
$Z - 1 = Y$
$E - 1 = D$
Thus,the code for $FREEZE$ becomes $EQDDYD$.
Hence,the correct answer is $D$.