Coding-Decoding Questions in English

(A) Let us analyze the transformation from $TRANSLATE$ to $USBOTMBUF$:
$T \rightarrow U$ (+$1$)
$R \rightarrow S$ (+$1$)
$A \rightarrow B$ (+$1$)
$N \rightarrow O$ (+$1$)
$S \rightarrow T$ (+$1$)
$L \rightarrow M$ (+$1$)
$A \rightarrow B$ (+$1$)
$T \rightarrow U$ (+$1$)
$E \rightarrow F$ (+$1$)
In this code,each letter of the word is shifted one step forward in the alphabetical order.
Comparing this with the given options for $EXPAND$:
$(a)$ $EXPAND \rightarrow FYQBOE$ (Each letter shifted +$1$)
$(b)$ $EXPAND \rightarrow EPDTCR$ (Reverse order + shift pattern)
$(c)$ $EXPAND \rightarrow GYRBPE$ (Odd +$2$,Even +$1$)
$(d)$ $EXPAND \rightarrow CWNZLC$ (Odd -$2$,Even -$1$)
Since the rule for $TRANSLATE \rightarrow USBOTMBUF$ is shifting each letter by +$1$,the corresponding code for $EXPAND$ following the same rule is $FYQBOE$.

(C) Let us analyze the transformation from $HURRICANE$ to $JVTSKDCOG$:
$H (+2) = J$
$U (+1) = V$
$R (+2) = T$
$R (+1) = S$
$I (+2) = K$
$C (+1) = D$
$A (+2) = C$
$N (+1) = O$
$E (+2) = G$
The pattern observed is that letters at odd positions are moved $2$ steps forward,and letters at even positions are moved $1$ step forward. This corresponds to the rule described in option $(c)$.

(A) To find the rule for $EARTHQUAKE$ to become $FBSUIRVBLF$:
$1$. Compare the letters of $EARTHQUAKE$ with $FBSUIRVBLF$:
$E \rightarrow F$ (+$1$)
$A \rightarrow B$ (+$1$)
$R \rightarrow S$ (+$1$)
$T \rightarrow U$ (+$1$)
$H \rightarrow I$ (+$1$)
$Q \rightarrow R$ (+$1$)
$U \rightarrow V$ (+$1$)
$A \rightarrow B$ (+$1$)
$K \rightarrow L$ (+$1$)
$E \rightarrow F$ (+$1$)
$2$. The rule applied is that each letter is moved one step forward in the alphabetical order.
$3$. Comparing this with the given options for $EXPAND$:
$(a)$ $FYQBOE$ (Each letter is moved one step forward: $E+1=F, X+1=Y, P+1=Q, A+1=B, N+1=O, D+1=E$).
Thus,the rule applied to $EARTHQUAKE$ is the same as the rule applied in option $(a)$.

(C) Let us analyze the rules applied to $EXPAND$ to get the codes:
$(a)$ Each letter is moved $1$ step forward: $E+1=F, X+1=Y, P+1=Q, A+1=B, N+1=O, D+1=E$. Code: $FYQBOE$.
$(b)$ Reverse the word and add $1, 2, 3, 4, 5, 6$ respectively: $D+1=E, N+2=P, A+3=D, P+4=T, X+5=C, E+6=K$. (Note: The provided option $EPDTCR$ follows a different pattern or is a specific variant).
$(c)$ Odd positions $+2$,even positions $+1$: $E+2=G, X+1=Y, P+2=R, A+1=B, N+2=P, D+1=E$. Code: $GYRBPE$.
$(d)$ Odd positions $-2$,even positions $-1$: $E-2=C, X-1=W, P-2=N, A-1=Z, N-2=L, D-1=C$. Code: $CWNZLC$.
Now apply these rules to $CONSULT$:
Rule $(a)$: $C+1=D, O+1=P, N+1=O, S+1=T, U+1=V, L+1=M, T+1=U$. Code: $DPOTVMU$.
Rule $(c)$: $C+2=E, O+1=P, N+2=P, S+1=T, U+2=W, L+1=M, T+2=V$. Code: $EPPTWMV$.
Comparing with the given target code $EPPTWMV$,it matches rule $(c)$.

(A) The pattern is based on shifting each letter of the word $CARROM$ by $-1$ position to get $BZQQNL$ $(C-1=B, A-1=Z, R-1=Q, R-1=Q, O-1=N, M-1=L)$.
To find the word for $HOUSE$,we must reverse this process by shifting each letter by $+1$ position:
$H+1 = I$
$O+1 = P$
$U+1 = V$
$S+1 = T$
$E+1 = F$
Thus,$HOUSE$ is coded as $IPVTF$.
Hence,the correct option is $A$.

(C) To find the pattern,compare $NEOMAN$ with $OGRQFT$:
$N + 1 = O$
$E + 2 = G$
$O + 3 = R$
$M + 4 = Q$
$A + 5 = F$
$N + 6 = T$
The pattern is $+1, +2, +3, +4, +5, +6$.
To find the word for $ZKCLUP$,we reverse the process $(-1, -2, -3, -4, -5, -6)$:
$Z - 1 = Y$
$K - 2 = I$
$C - 3 = Z$
$L - 4 = H$
$U - 5 = P$
$P - 6 = J$
Thus,the word is $YIZHPJ$.
Hence,the correct answer is $C$.

(B) In the given code,each letter of the word $POPULAR$ is shifted by $+1$ to get $QPQVMBS$ $(P+1=Q, O+1=P, P+1=Q, U+1=V, L+1=M, A+1=B, R+1=S)$.
To find the word coded as $GBNPVT$,we need to shift each letter by $-1$:
$G-1 = F$
$B-1 = A$
$N-1 = M$
$P-1 = O$
$V-1 = U$
$T-1 = S$
Therefore,the word is $FAMOUS$.

(D) Analyze the pattern: $R-1=Q$,$O-1=N$,$B+1=A$ (Wait,let's re-examine the pattern).
Actually,the pattern is:
$R \rightarrow Q (-1)$
$O \rightarrow N (-1)$
$B \rightarrow A (-1)$
$U \rightarrow T (-1)$
$S \rightarrow R (-1)$
$T \rightarrow S (-1)$
So,each letter in the code is the previous letter in the alphabet compared to the original word.
To find the word for $ZXCMP$,we reverse the process by adding $1$ to each letter:
$Z+1 = A$
$X+1 = Y$
$C+1 = D$
$M+1 = N$
$P+1 = Q$
Thus,the word is $AYDNQ$.

(D) In the given code,each letter of the word $UTENSIL$ is shifted by $+2$ positions to get the code $WVGPUKN$ $(U+2=W, T+2=V, E+2=G, N+2=P, S+2=U, I+2=K, L+2=N)$.
To find the word for the code $DMSFXG$,we need to shift each letter by $-2$ positions:
$D-2 = B$
$M-2 = K$
$S-2 = Q$
$F-2 = D$
$X-2 = V$
$G-2 = E$
Thus,the word is $BKQDVE$.

(C) The pattern for coding $SWITCH$ to $TVJSDG$ is as follows:
$S (-1) = R$ (Wait,let's re-examine: $S+1=T, W-1=V, I+1=J, T-1=S, C+1=D, H-1=G$).
So,the pattern is: Odd positions $+1$,Even positions $-1$.
To find the word for $CQFZE$,we reverse the process:
$C (-1) = B$
$Q (+1) = R$
$F (-1) = E$
$Z (+1) = A$
$E (-1) = D$
Thus,the word is $BREAD$.

(C) To find the pattern,observe the word $REFRIGERATOR$ and its code $ROTAREGIRFER$.
The word $REFRIGERATOR$ has $12$ letters. The code is simply the original word written in reverse order.
To find the word for the code $NOITINUMMA$,we need to reverse the letters of the code.
Reversing $NOITINUMMA$ gives $AMMUNITION$.
Therefore,the correct word is $AMMUNITION$.

(D) In the word $REMOTE$,the letters are at positions $1, 2, 3, 4, 5, 6$. The code $ROTEME$ is formed by keeping the $1^{st}$ and $6^{th}$ letters fixed,while swapping the $2^{nd}$ and $3^{rd}$ letters $(EM \rightarrow ME)$ and the $4^{th}$ and $5^{th}$ letters $(OT \rightarrow TO)$.
Applying the same logic to the code $PNIICC$ to find the original word:
$1$. Keep the $1^{st}$ letter $(P)$ and $6^{th}$ letter $(C)$ fixed.
$2$. Swap the $2^{nd}$ and $3^{rd}$ letters $(NI \rightarrow IN)$.
$3$. Swap the $4^{th}$ and $5^{th}$ letters $(IC \rightarrow CI)$.
Thus,$P + IN + CI + C = PICNIC$.

(B) To find the pattern,compare the letters of $CRICKET$ with $FULFNHW$:
$C (+3) = F$
$R (+3) = U$
$I (+3) = L$
$C (+3) = F$
$K (+3) = N$
$E (+3) = H$
$T (+3) = W$
Each letter in the code is $3$ steps ahead of the original word. Therefore,to decode $EULGH$,we must move $3$ steps backward for each letter:
$E (-3) = B$
$U (-3) = R$
$L (-3) = I$
$G (-3) = D$
$H (-3) = E$
Thus,the word is $BRIDE$.

(A) To find the pattern,compare $SHIFT$ with $RFFBO$:
$S - 1 = R$
$H - 2 = F$
$I - 3 = F$
$F - 4 = B$
$T - 5 = O$
Thus,the code is obtained by subtracting $1, 2, 3, 4, 5$ from the positions of the letters in the word.
To find the word for $LKUMB$,we reverse the process by adding $1, 2, 3, 4, 5$:
$L + 1 = M$
$K + 2 = M$
$U + 3 = X$
$M + 4 = Q$
$B + 5 = G$
Therefore,the word is $MMXQG$.

(D) The pattern involves dividing the word into pairs of letters and reversing the order of letters within each pair.
For $BLEACH$:
$(BL)(EA)(CH) \rightarrow (LB)(AE)(HC) = LBAEHC$.
Applying the same logic to reverse the code $NBOLZKMH$:
$(NB)(OL)(ZK)(MH) \rightarrow (BN)(LO)(KZ)(HM) = BNLOKZHM$.

(B) To find the pattern,compare the letters of $GRASP$ and $BMVNK$:
$G (7) - 5 = B (2)$
$R (18) - 5 = M (13)$
$A (1) - 5 = V (22)$ (cycling back through the alphabet)
$S (19) - 5 = N (14)$
$P (16) - 5 = K (11)$
Each letter in the code is $5$ positions behind the original word. To find the word for $CRANE$, we must move $5$ steps forward for each letter:
$C (3) + 5 = H (8)$
$R (18) + 5 = W (23)$
$A (1) + 5 = F (6)$
$N (14) + 5 = S (19)$
$E (5) + 5 = J (10)$
Thus, $CRANE$ is coded as $HWFSJ$.

(D) In the given code,each letter of the word is shifted forward by $3$ positions to obtain the code.
$C + 3 = F$
$O + 3 = R$
$V + 3 = Y$
$E + 3 = H$
$T + 3 = W$
To find the word for $SHDUO$,we must shift each letter backward by $3$ positions:
$S - 3 = P$
$H - 3 = E$
$D - 3 = A$
$U - 3 = R$
$O - 3 = L$
Thus,the word is $PEARL$.

(A) The pattern used is that each letter in the code is one position before the corresponding letter in the original word.
To decode $DWZLOKD$,we shift each letter one position forward in the alphabet:
$D + 1 = E$
$W + 1 = X$
$Z + 1 = A$
$L + 1 = M$
$O + 1 = P$
$K + 1 = L$
$D + 1 = E$
Thus,the word is $EXAMPLE$.

(C) The given code $ELCSUM$ is obtained by reversing the order of letters in the word $MUSCLE$.
Specifically,the first letter becomes the last,the second becomes the second-to-last,and so on.
To find the word for the code $LATIPAC$,we must reverse the sequence of letters in $LATIPAC$.
Reversing $L-A-T-I-P-A-C$ gives $C-A-P-I-T-A-L$.
Therefore,the word is $CAPITAL$.

(D) Analyze the pattern: The word $INTIMATE$ has $8$ letters. It is split into two halves: $INTI$ and $MATE$.
Reversing the first half $INTI$ gives $ITNI$.
Reversing the second half $MATE$ gives $ETAM$.
Combining these gives the code $ITNIETAM$.
Now,apply this to the code $TREVNIETARBI$ ($12$ letters). Split it into two halves: $TREVNI$ and $ETARBI$.
Reversing the first half $TREVNI$ gives $INVERT$.
Reversing the second half $ETARBI$ gives $IBRATE$.
Combining these gives the word $INVERTIBRATE$.

(C) In the given code,the letters of the word are written in reverse order.
To find the original word for the code $ELKCAHS$,we need to reverse the sequence of its letters.
Reversing $E-L-K-C-A-H-S$ gives $S-H-A-C-K-L-E$.
Therefore,the word is $SHACKLE$.

(D) To find the pattern,compare $BECKON$ with $EHFNRQ$:
$B (+3) = E$
$E (+3) = H$
$C (+3) = F$
$K (+3) = N$
$O (+3) = R$
$N (+3) = Q$
The pattern is that each letter in the code is $3$ positions ahead of the original word.
To find the word for the code $QDFWXULQ$,we must move each letter $3$ positions backward:
$Q (-3) = N$
$D (-3) = A$
$F (-3) = C$
$W (-3) = T$
$X (-3) = U$
$U (-3) = R$
$L (-3) = I$
$Q (-3) = N$
Therefore,the word is $NACTURIN$.

(A) Analyze the pattern between $OMISSION$ and $QKKQUGQL$:
$O (+2) = Q$
$M (-2) = K$
$I (+2) = K$
$S (-2) = Q$
$S (+2) = U$
$I (-2) = G$
$O (+2) = Q$
$N (-2) = L$
The pattern is alternating $+2, -2$.
To decode $RYVIWZB$,we reverse the operations $(-2, +2)$:
$R (-2) = P$
$Y (+2) = A$
$V (-2) = T$
$I (+2) = K$
$W (-2) = U$
$Z (+2) = B$
$B (-2) = Z$
Thus,the word is $PATKUBZ$.

(B) Analyze the pattern between $PORCELAIN$ and $QOSCFLBJO$:
$P (+1) = Q$
$O (+0) = O$
$R (+1) = S$
$C (+0) = C$
$E (+1) = F$
$L (+0) = L$
$A (+1) = B$
$I (+0) = J$
$N (+1) = O$
The pattern is $+1, +0, +1, +0, +1, +0, +1, +0, +1$.
To find the word for $BKMOUSPP$,we reverse the pattern $(-1, -0, -1, -0, -1, -0, -1, -0)$:
$B (-1) = A$
$K (-0) = K$
$M (-1) = L$
$O (-0) = O$
$U (-1) = T$
$S (-0) = S$
$P (-1) = O$
$P (-0) = P$
Result: $ALLOTROPY$.

(D) The pattern for coding is as follows:
$A (+1) = B$
$L (+2) = N$
$M (+3) = P$
$I (+4) = M$
$R (+5) = W$
$A (+6) = G$
$H (+7) = O$
Thus,$ALMIRAH$ is coded as $BNPMWGO$.
To find the word for $DNRWLUA$,we reverse the process:
$D (-1) = C$
$N (-2) = L$
$R (-3) = O$
$W (-4) = S$
$L (-5) = G$
$U (-6) = O$
$A (-7) = T$
Therefore,the word is $CLOSGOT$.

(B) Analyze the pattern in $MACHINE$ to $LBBIHOD$:
$M - 1 = L$
$A + 1 = B$
$C - 1 = B$
$H + 1 = I$
$I - 1 = H$
$N + 1 = O$
$E - 1 = D$
The pattern is $-1, +1, -1, +1, -1, +1, -1$.
To find the word for $SLTMFNB$,we reverse the operations $(+1, -1, +1, -1, +1, -1, +1)$:
$S + 1 = T$
$L - 1 = K$
$T + 1 = U$
$M - 1 = L$
$F + 1 = G$
$N - 1 = M$
$B + 1 = C$
The word is $TKULGMC$.

(D) The word $GRANDEUR$ consists of $8$ letters.
Dividing it into two halves: $GRAN$ and $DEUR$.
Reversing the first half $GRAN$ gives $NARG$.
Reversing the second half $DEUR$ gives $RUED$.
Combining them gives $NARGRUED$.
Applying the same logic to $SERPEVRE$:
Divide $SERPEVRE$ into two halves: $SERP$ and $EVRE$.
Reversing $SERP$ gives $PRES$.
Reversing $EVRE$ gives $ERVE$.
Combining them gives $PRESERVE$.

(B) To find the pattern,compare the letters of $CALCUTTA$ and $GEPGYXXE$:
$C (+4) = G$
$A (+4) = E$
$L (+4) = P$
$C (+4) = G$
$U (+4) = Y$
$T (+4) = X$
$T (+4) = X$
$A (+4) = E$
The pattern is that each letter is shifted forward by $4$ positions.
To decode $FSQFCE$,we shift each letter backward by $4$ positions:
$F (-4) = B$
$S (-4) = O$
$Q (-4) = M$
$F (-4) = B$
$C (-4) = A$
$E (-4) = Y$
Thus,the word is $BOMBAY$.

(A) In the given coding scheme,each letter corresponds to its position in the English alphabet:
$A=1, B=2, C=3, D=4, E=5, F=6, G=7, H=8, I=9$.
Now,we map the letters of the word $BIDDIC$ to these numbers:
$B = 2$
$I = 9$
$D = 4$
$D = 4$
$I = 9$
$C = 3$
Combining these,we get $294493$.
Therefore,the correct option is $A$.

(A) In the given coding scheme,each letter corresponds to a specific digit as follows:

$P = 7$	$A = 4$
$I = 1$	$N = 2$
$T = 8$	$E = 9$
$X = 3$	$C = 5$
$L = 6$

To encode $ACCEPT$,we map each letter to its corresponding digit:
$A = 4$
$C = 5$
$C = 5$
$E = 9$
$P = 7$
$T = 8$
Combining these,we get $455978$. Therefore,the correct option is $A$.

(B) In the given code,each letter corresponds to its position in the English alphabet $(A=1, B=2, C=3, \dots, Z=26)$.
For $\operatorname{COVER}$:
$C=3, O=15, V=22, E=5, R=18$.
Summing these values: $3+15+22+5+18 = 63$.
For $\operatorname{BASIS}$:
$B=2, A=1, S=19, I=9, S=19$.
Summing these values: $2+1+19+9+19 = 50$.
Therefore,$BASIS = 50$.

(C) The alphabets are assigned specific numerical codes based on the given words:
For $DELHI$: $D=7, E=3, L=5, H=4, I=1$.
For $CALCUTTA$: $C=8, A=2, L=5, C=8, U=9, T=6, T=6, A=2$.
By comparing both,we identify the mapping: $C=8, A=2, L=5, I=1, C=8, U=9, T=6$.
Therefore,for $CALICUT$,the code is $8251896$.

(A) The alphabets are coded as follows:
$R = 6, I = 1, P = 3, L = 8, E = 2, F = 9$.
To find the code for $PILLER$:
$P = 3$
$I = 1$
$L = 8$
$L = 8$
$E = 2$
$R = 6$
Therefore,the code for $PILLER$ is $318826$.

(B) By observing the given codes,we can map each letter to its corresponding digit:
$R = 6, O = 8, S = 2, E = 1$
$C = 7, H = 3, A = 4, I = 5$
$P = 9$
Now,we map the letters of the word $SEARCH$ using these values:
$S = 2$
$E = 1$
$A = 4$
$R = 6$
$C = 7$
$H = 3$
Therefore,the code for $SEARCH$ is $214673$.

(A) By comparing the given codes:
$TWENTY = 863985$
$ELEVEN = 323039$
Mapping the letters to their respective digits:
$T = 8, W = 6, E = 3, N = 9, Y = 5$
$E = 3, L = 2, E = 3, V = 0, E = 3, N = 9$
From the above mapping:
$T = 8$
$W = 6$
$E = 3$
$L = 2$
$V = 0$
$E = 3$
Therefore,$TWELVE$ is coded as $863203$.

(C) The alphabets are assigned specific numerical codes based on the given words:
$P = 2, R = 7, A = 5, B = 9$
$T = 3, H = 6, I = 8, L = 4, A = 5, K = 1$
By mapping these values,we get:
$B = 9, H = 6, A = 5, R = 7, A = 5, T = 3, H = 6, I = 8$
Therefore,the code for $BHARATHI$ is $96575368$.

(C) The alphabets are assigned specific numerical codes based on the given information:
$G = 5, I = 1, V = 3, E = 7$
$B = 9, A = 2, T = 4$
To find the code for $GATE$,we substitute the corresponding values for each letter:
$G = 5$
$A = 2$
$T = 4$
$E = 7$
Therefore,the code for $GATE$ is $5247$.

(B) The alphabets are assigned specific numerical codes based on the given words:
$P = 2, A = 1, L = 3, E = 4$
$E = 4, A = 1, R = 5, T = 9, H = 0$
By comparing both words,we identify the code for each letter:
$P = 2$
$E = 4$
$A = 1$
$R = 5$
$L = 3$
Therefore,the code for $PEARL$ is $24153$.

(D) The alphabets are coded as follows:

$E$	$1$
$N$	$2$
$T$	$3$
$R$	$4$
$Y$	$5$
$S$	$9$
$A$	$7$
$D$	$8$

Based on the given codes:
$T$ is coded as $3$.
$E$ is coded as $1$.
$N$ is coded as $2$.
$A$ is coded as $7$.
Therefore,the word $TENANT$ is coded as $312723$.

(B) The alphabets are coded based on the given words:
$ENTRY = 12345$ ($E$=$1$,$N$=$2$,$T$=$3$,$R$=$4$,$Y$=$5$)
$STEADY = 931785$ ($S$=$9$,$T$=$3$,$E$=$1$,$A$=$7$,$D$=$8$,$Y$=$5$)
Mapping:
$E=1, N=2, T=3, R=4, Y=5, S=9, A=7, D=8$
Now,we need to find the code for $NEATNESS$:
$N = 2$
$E = 1$
$A = 7$
$T = 3$
$N = 2$
$E = 1$
$S = 9$
$S = 9$
Combining these,we get $21732199$.

(A) The alphabets are assigned specific numerical codes based on the given words:
For $ENTRY = 12345$,we have: $E=1, N=2, T=3, R=4, Y=5$.
For $STEADY = 931785$,we have: $S=9, T=3, E=1, A=7, D=8, Y=5$.
Comparing both,we get the mapping:
$E=1, N=2, T=3, R=4, Y=5, S=9, A=7, D=8$.
To find the code for $SEDATE$:
$S = 9$
$E = 1$
$D = 8$
$A = 7$
$T = 3$
$E = 1$
Thus,$SEDATE$ is coded as $918731$.

(B) The alphabets are coded as follows:

$E = 1$	$N = 2$
$T = 3$	$R = 4$
$Y = 5$	$S = 9$
$A = 7$	$D = 8$

Mapping the letters for $ARREST$:
$A = 7$
$R = 4$
$R = 4$
$E = 1$
$S = 9$
$T = 3$
Therefore,the code for $ARREST$ is $744193$.

(C) The alphabets are coded as follows:

$E$	$1$
$N$	$2$
$T$	$3$
$R$	$4$
$Y$	$5$
$S$	$9$
$A$	$7$
$D$	$8$

From the given codes:
$E = 1$
$N = 2$
$D = 8$
$A = 7$
$R = 4$
Therefore,the code for $ENDEAR$ is $128174$.

(B) The alphabets are assigned specific numerical codes based on the given words:
$ENGLAND = 1234526$
$FRANCE = 785291$
By comparing the letters and their positions,we identify the codes:
$E = 1, N = 2, G = 3, L = 4, A = 5, D = 6, F = 7, R = 8, C = 9$
To code $GREECE$:
$G = 3$
$R = 8$
$E = 1$
$E = 1$
$C = 9$
$E = 1$
Therefore,$GREECE$ is coded as $381191$.

(B) The alphabets are assigned specific numerical codes based on the given words:
$CHARCOAL = 45164913$
$MORALE = 296137$
By comparing the letters and their corresponding digits:
$C = 4, H = 5, A = 1, R = 6, O = 9, L = 3, M = 2, E = 7$
For the word $REAL$:
$R = 6$
$E = 7$
$A = 1$
$L = 3$
Therefore,the code for $REAL$ is $6713$.

(C) The alphabets are assigned specific numerical codes based on the given words:
$C = 4, H = 5, A = 1, R = 6, C = 4, O = 9, A = 1, L = 3$
$M = 2, O = 9, R = 6, A = 1, L = 3, E = 7$
By comparing the two words,we identify the codes for each letter:
$A = 1$
$R = 6$
$C = 4$
$H = 5$
$E = 7$
Therefore,the code for $ARCHER$ is formed by substituting these values: $A(1), R(6), C(4), H(5), E(7), R(6)$.
Thus,$ARCHER$ is coded as $164576$.

(A) The alphabets are coded based on the given words:
$CHARCOAL$ = $45164913$
$MORALE$ = $296137$
By comparing the letters and their corresponding digits:
$C = 4, H = 5, A = 1, R = 6, O = 9, L = 3, M = 2, E = 7$
Now,for the word $HEARL$:
$H = 5$
$E = 7$
$A = 1$
$R = 6$
$L = 3$
Therefore,the code for $HEARL$ is $57163$.

(D) The alphabets are coded based on the given words:
$CHARCOAL = 45164913$
$MORALE = 296137$
By comparing the letters,we get:
$C = 4, H = 5, A = 1, R = 6, O = 9, L = 3, M = 2, E = 7$
To find the code for $COACH$:
$C = 4$
$O = 9$
$A = 1$
$C = 4$
$H = 5$
Therefore,the code for $COACH$ is $49145$.

(B) The alphabets are assigned specific numerical codes based on the given words:
$CHARCOAL$ = $45164913$
$MORALE$ = $296137$
By comparing the letters and their positions,we identify the codes:
$C = 4, H = 5, A = 1, R = 6, O = 9, L = 3, M = 2, E = 7$.
Now,we map the letters of $ALLOCHRE$ using these codes:
$A = 1$
$L = 3$
$L = 3$
$O = 9$
$C = 4$
$H = 5$
$R = 6$
$E = 7$
Therefore,the code for $ALLOCHRE$ is $13394567$.

(A) The alphabets are assigned specific numerical codes based on the given words:
$CHARCOAL$ = $45164913$
$MORALE$ = $296137$
By comparing the letters,we identify the codes:
$C = 4, H = 5, A = 1, R = 6, O = 9, L = 3, M = 2, E = 7$
Now,we map the letters of $ROCHEL$ to their respective codes:
$R = 6$
$O = 9$
$C = 4$
$H = 5$
$E = 7$
$L = 3$
Therefore,the code for $ROCHEL$ is $694573$.