You are given two samples of water labelled as $A$ and $B$. Sample $A$ boils at $100\,^{\circ}C$ and sample $B$ boils at $102\,^{\circ}C$. Which sample of water will not freeze at $0\,^{\circ}C$? Comment.
(B) Sample $B$ will not freeze at $0\,^{\circ}C$ because it is not pure water.
At $1 \text{ atm}$ pressure,the boiling point of pure water is $100\,^{\circ}C$ and its freezing point is $0\,^{\circ}C$.
Since sample $B$ boils at $102\,^{\circ}C$,it indicates the presence of impurities (solutes) dissolved in the water.
The presence of impurities leads to the phenomenon of freezing point depression,meaning the freezing point of the solution will be lower than $0\,^{\circ}C$.
At $1 \text{ atm}$ pressure,the boiling point of pure water is $100\,^{\circ}C$ and its freezing point is $0\,^{\circ}C$.
Since sample $B$ boils at $102\,^{\circ}C$,it indicates the presence of impurities (solutes) dissolved in the water.
The presence of impurities leads to the phenomenon of freezing point depression,meaning the freezing point of the solution will be lower than $0\,^{\circ}C$.
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