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(A) Let the resistance of each resistor be $R$. We can combine these three resistors in the following ways:$1$. All three in series: $R_{eq} = R + R +

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four

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(A) Let the resistance of each resistor be $R$. We can combine these three resistors in the following ways:$1$. All three in series: $R_{eq} = R + R + R = 3R$.$2$. All three in parallel: $1/R_{eq} = 1/R + 1/R + 1/R = 3/R$,so $R_{eq} = R/3$.$3$. Two in series and one in parallel with them: $R_{eq} = (2R 	imes R) / (2R + R) = 2R^2 / 3R = (2/3)R$.$4$. Two in parallel and one in series with them: $R_{eq} = R + (R 	imes R) / (R + R) = R + R/2 = (3/2)R$.Thus,there are $4$ distinct equivalent resistance values that can be obtained.

You are given three equal resistors. The number of resistances which can be obtained by joining them in series and in parallel grouping is

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