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(B) According to Ohm's Law,$V = IR$,where $V$ is the potential difference,$I$ is the current,and $R$ is the resistance of the conductor.If the resista

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It will be doubled.

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(B) According to Ohm's Law,$V = IR$,where $V$ is the potential difference,$I$ is the current,and $R$ is the resistance of the conductor.If the resistance $R$ remains constant,then $I = V/R$.If the potential difference $V$ is doubled $(V' = 2V)$,the new current $I'$ becomes $I' = V'/R = (2V)/R = 2(V/R) = 2I$.Therefore,the current flowing through the conductor is also doubled.

What will happen to the current flowing through a conductor,if the potential difference is doubled?

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