You are given 500 mL of 2 N HCl and 500 m | vedclass

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(B) For $HCl$,normality $(N)$ is equal to molarity $(M)$ because the $n$-factor is $1$.Let $V$ be the volume of $5 \ M \ HCl$ used to mix with the ent

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$750$

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(B) For $HCl$,normality $(N)$ is equal to molarity $(M)$ because the $n$-factor is $1$.Let $V$ be the volume of $5 \ M \ HCl$ used to mix with the entire $500 \ mL$ of $2 \ M \ HCl$ to obtain a $3 \ M$ solution.Using the formula $M_{mix} = \frac{M_1V_1 + M_2V_2}{V_1 + V_2}$:$3 = \frac{2 	imes 500 + 5 	imes V}{500 + V}$$3(500 + V) = 1000 + 5V$$1500 + 3V = 1000 + 5V$$500 = 2V$$V = 250 \ mL$Total volume $= 500 \ mL + 250 \ mL = 750 \ mL$.

You are given $500 \ mL$ of $2 \ N \ HCl$ and $500 \ mL$ of $5 \ N \ HCl$. What will be the maximum volume of $3 \ M \ HCl$ that you can make from these two solutions? .............. $mL$

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