Write the unit of the rate constant for the following reactions:
$1.$ $\frac{1}{2}$ order
$2.$ $\frac{3}{2}$ order
$1.$ $\frac{1}{2}$ order
$2.$ $\frac{3}{2}$ order
The general formula for the unit of the rate constant $k$ for a reaction of order $n$ is given by:
Unit $= (mol \ L^{-1})^{1-n} \ s^{-1}$
$1.$ For a reaction of order $n = \frac{1}{2}$:
Unit $= (mol \ L^{-1})^{1 - 1/2} \ s^{-1} = (mol \ L^{-1})^{1/2} \ s^{-1} = mol^{1/2} \ L^{-1/2} \ s^{-1}$
$2.$ For a reaction of order $n = \frac{3}{2}$:
Unit $= (mol \ L^{-1})^{1 - 3/2} \ s^{-1} = (mol \ L^{-1})^{-1/2} \ s^{-1} = mol^{-1/2} \ L^{1/2} \ s^{-1}$
Unit $= (mol \ L^{-1})^{1-n} \ s^{-1}$
$1.$ For a reaction of order $n = \frac{1}{2}$:
Unit $= (mol \ L^{-1})^{1 - 1/2} \ s^{-1} = (mol \ L^{-1})^{1/2} \ s^{-1} = mol^{1/2} \ L^{-1/2} \ s^{-1}$
$2.$ For a reaction of order $n = \frac{3}{2}$:
Unit $= (mol \ L^{-1})^{1 - 3/2} \ s^{-1} = (mol \ L^{-1})^{-1/2} \ s^{-1} = mol^{-1/2} \ L^{1/2} \ s^{-1}$
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Which is True $(T)$ and False $(F)$ in the following statement?
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The order of this reaction is $1$.
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$2) NOBr_{2(g)} + NO_{(g)} \rightarrow 2NOBr_{(g)}$ (slow)
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If the second step is the rate-determining step,what is the order of the reaction with respect to $NO_{(g)}$?
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View SolutionThe rate constants for the following reactions are:
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Reaction $2$: $A \xrightarrow{\text{catalyst } 2} P_2, k_2 = 0.1 \ L \ mol^{-1} \ s^{-1}$
Reaction $3$: $A \xrightarrow{\text{catalyst } 3} P_3, k_3 = 0.01 \ L^2 \ mol^{-2} \ s^{-1}$
What is the correct relation between the rates of the reactions at $[A] = 1 \ M$?
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Reaction $3$: $A \xrightarrow{\text{catalyst } 3} P_3, k_3 = 0.01 \ L^2 \ mol^{-2} \ s^{-1}$
What is the correct relation between the rates of the reactions at $[A] = 1 \ M$?
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