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(B) The statement is False.We know that in the interval $0^{\circ} < 	heta < 90^{\circ}$,the function $\sin 	heta$ is an increasing function,while $

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False

Vedclass · Answer

(B) The statement is False.We know that in the interval $0^{\circ} At $	heta = 45^{\circ}$,$\sin 45^{\circ} = \cos 45^{\circ} = \frac{1}{\sqrt{2}}$.For any angle $	heta$ such that $45^{\circ}  \cos 	heta$.Since $80^{\circ}$ lies in the interval $(45^{\circ}, 90^{\circ})$,we have $\sin 80^{\circ} > \cos 80^{\circ}$.Therefore,$(\sin 80^{\circ} - \cos 80^{\circ}) > 0$,which means the value is positive,not negative.

Write 'True' or 'False' and justify your answer.
The value of the expression $(\sin 80^{\circ} - \cos 80^{\circ})$ is negative.

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Write 'True' or 'False' and justify your answer.The value of the expression $(\sin 80^{\circ} - \cos 80^{\circ})$ is negative.