Write the first five terms of the sequence wh | vedclass

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(A) To find the first five terms,we substitute $n = 1, 2, 3, 4, 5$ into the formula $a_{n} = (-1)^{n-1} 5^{n+1}$.For $n = 1$: $a_{1} = (-1)^{1-1} 5^{1

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$25, -125, 625, -3125, 15625$

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(A) To find the first five terms,we substitute $n = 1, 2, 3, 4, 5$ into the formula $a_{n} = (-1)^{n-1} 5^{n+1}$.For $n = 1$: $a_{1} = (-1)^{1-1} 5^{1+1} = (-1)^{0} 5^{2} = 1 	imes 25 = 25$.For $n = 2$: $a_{2} = (-1)^{2-1} 5^{2+1} = (-1)^{1} 5^{3} = -1 	imes 125 = -125$.For $n = 3$: $a_{3} = (-1)^{3-1} 5^{3+1} = (-1)^{2} 5^{4} = 1 	imes 625 = 625$.For $n = 4$: $a_{4} = (-1)^{4-1} 5^{4+1} = (-1)^{3} 5^{5} = -1 	imes 3125 = -3125$.For $n = 5$: $a_{5} = (-1)^{5-1} 5^{5+1} = (-1)^{4} 5^{6} = 1 	imes 15625 = 15625$.Thus,the first five terms are $25, -125, 625, -3125, 15625$.

Write the first five terms of the sequence whose $n^{th}$ term is $a_{n} = (-1)^{n-1} 5^{n+1}$.

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