Write the first five terms of the sequences whose $n^{t h}$ term is $a_{n}=(-1)^{n-1} 5^{n+1}$

Vedclass pdf generator app on play store
Vedclass iOS app on app store

Substituting $n=1,2,3,4,5,$ we obtain

$a_{1}=(-1)^{1-1} 5^{1+1}=5^{2}=25$

$a_{2}=(-1)^{2-1} 5^{2+1}=-5^{3}=-125$

$a_{3}=(-1)^{3-1} 5^{3+1}=5^{4}=625$

$a_{4}=(-1)^{4-1} 5^{4+1}=-5^{5}=-3125$

$a^{5}=(-1)^{5-1} 5^{5+1}=5^{6}=15625$

Therefore, the required terms are $25,-125,625,-3125$ and $15625 .$

Similar Questions

If $x,y,z$ are in $A.P. $ and ${\tan ^{ - 1}}x,{\tan ^{ - 1}}y$ and ${\tan ^{ - 1}}z$ are also in $A.P.$, then

Suppose $a_{1}, a_{2}, \ldots, a_{ n }, \ldots$ be an arithmetic progression of natural numbers. If the ratio of the sum of the first five terms of the sum of first nine terms of the progression is $5: 17$ and $110< a_{15} < 120$ , then the sum of the first ten terms of the progression is equal to -

  • [JEE MAIN 2022]

Let $a_1, a_2, \ldots \ldots, a_n$ be in A.P. If $a_5=2 a_3$ and $a_{11}=18$, then $12\left(\frac{1}{\sqrt{a_{10}}+\sqrt{a_{11}}}+\frac{1}{\sqrt{a_{11}}+\sqrt{a_{12}}}+\ldots . \cdot \frac{1}{\sqrt{a_{17}}+\sqrt{a_{18}}}\right)$ is equal to $..........$.

  • [JEE MAIN 2023]

Let $a_n, n \geq 1$, be an arithmetic progression with first term $2$ and common difference $4$ . Let $M_n$ be the average of the first $n$ terms. Then the sum $\sum \limits_{n=1}^{10} M_n$ is

  • [KVPY 2019]

The common difference of the $A.P.$ $b_{1}, b_{2}, \ldots,$ $b_{ m }$ is $2$ more than the common difference of $A.P.$ $a _{1}, a _{2}, \ldots, a _{ n } .$ If $a _{40}=-159, a _{100}=-399$ and $b _{100}= a _{70},$ then $b _{1}$ is equal to

  • [JEE MAIN 2020]