Write the coefficient of $x^{2}$ in the following polynomial:
$\sqrt{5}x^{2} - 7x + 13$

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(N/A) The given polynomial is $p(x) = \sqrt{5}x^{2} - 7x + 13$.
The coefficient of $x^{2}$ is the numerical factor multiplying the $x^{2}$ term.
In this expression,the term containing $x^{2}$ is $\sqrt{5}x^{2}$.
Therefore,the coefficient of $x^{2}$ is $\sqrt{5}$.

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