Write the change in magnitude and direction of angular velocity with respect to time for a body rotating about a fixed axis.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) For a body rotating about a fixed axis,the angular velocity vector $\vec{\omega}$ is directed along the axis of rotation.
$1$. Magnitude: The magnitude of angular velocity,$\omega$,changes with time if the body undergoes angular acceleration $(\alpha = d\omega/dt \neq 0)$. If the rotation is uniform,the magnitude remains constant.
$2$. Direction: Since the axis of rotation is fixed,the direction of the angular velocity vector $\vec{\omega}$ remains constant (it always points along the fixed axis of rotation,determined by the right-hand rule).

Explore More

Similar Questions

What is the linear velocity if angular velocity $\vec{\omega} = 3 \hat{i} - 4 \hat{j} + \hat{k}$ and position vector $\vec{r} = 5 \hat{i} - 6 \hat{j} + 6 \hat{k}$?

$A$ mass $m$ is supported by a massless string wound around a uniform hollow cylinder of mass $m$ and radius $R$. If the string does not slip on the cylinder,then with what acceleration will the mass be released? (Assume $g =$ acceleration due to gravity)

$A$ thin rod is hinged at point $O$ and is in an unstable equilibrium position. It falls under the influence of gravity due to a slight disturbance. It makes angles of $60^{\circ}$,$90^{\circ}$,and $180^{\circ}$ with the vertical in positions $(2)$,$(3)$,and $(4)$ respectively. If $\omega_2$,$\omega_3$,and $\omega_4$ are the angular velocities in these positions,then:

$A$ string is wrapped around a disc of mass $M$ and radius $R$ and the free end is fixed to the ceiling. The centre of mass falls down as the disc unwinds the string. The tension in the string is

Difficult
View Solution

Two small balls are fixed at the ends of a light rigid rod of length $L = 0.4 \ m$. The system is released from a height $h = 5 \ m$ with the rod horizontal. The balls collide with the horizontal surface and rebound. The coefficient of restitution between ball $A$ and the ground is $e_A = 0.6$ and that between ball $B$ and the ground is $e_B = 0.4$. Find the angular speed (in $rad/s$) of the rod just after the collision. Take the acceleration due to gravity $g = 10 \ m/s^2$.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo