State the principle of a Wheatstone bridge.
(N/A) The principle of a Wheatstone bridge states that if four resistors $P, Q, R,$ and $S$ are arranged in a bridge configuration such that no current flows through the galvanometer $(I_g = 0)$,the bridge is said to be balanced.
In this balanced condition,the ratio of the resistances in the two arms is equal,which is given by the formula: $\frac{P}{Q} = \frac{R}{S}$.
This condition is achieved when the potential difference across the galvanometer is zero,meaning the potentials at the two connected points are equal.
In this balanced condition,the ratio of the resistances in the two arms is equal,which is given by the formula: $\frac{P}{Q} = \frac{R}{S}$.
This condition is achieved when the potential difference across the galvanometer is zero,meaning the potentials at the two connected points are equal.
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