Write the differential equation for an $LC$ circuit.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) In an $LC$ circuit consisting of an inductor $L$ and a capacitor $C$,the sum of the potential drops across the inductor and the capacitor must be zero according to Kirchhoff's voltage law.
Let $q$ be the charge on the capacitor at any time $t$.
The potential difference across the capacitor is $V_C = \frac{q}{C}$.
The potential difference across the inductor is $V_L = L \frac{di}{dt}$.
Since $i = \frac{dq}{dt}$,the current is the rate of change of charge.
Thus,$V_L = L \frac{d^2q}{dt^2}$.
Applying Kirchhoff's loop rule: $V_L + V_C = 0$.
Substituting the expressions: $L \frac{d^2q}{dt^2} + \frac{q}{C} = 0$.
This is the differential equation for the $LC$ circuit,which can also be written as $\frac{d^2q}{dt^2} + \frac{1}{LC} q = 0$.

Explore More

Similar Questions

In an $LC$ circuit,the angular frequency at resonance is $\omega$. What is the new angular frequency when the inductance is made four times and the capacitance is made eight times its original value?

An oscillator circuit consists of an inductance of $0.5 \ mH$ and a capacitor of $20 \ \mu F$. The resonant frequency of the circuit is nearly......$Hz$

$A$ capacitor of capacitance $C$ has initial charge $Q_0$ and is connected to an inductor of inductance $L$ as shown. At $t=0$,the switch $S$ is closed. Find the current through the inductor when the energy in the capacitor is three times the energy of the inductor.

$A$ capacitor of capacitance $2 \mu F$ is charged to a potential difference of $12 \, V$. It is then connected across an inductor of inductance $0.6 \, mH$. The current in the circuit when the potential difference across the capacitor is $6 \, V$ is :

Difficult
View Solution

Consider an $LC$ circuit,with inductance $L = 0.1 \ H$ and capacitance $C = 10^{-3} \ F$,kept on a plane. The area of the circuit is $1 \ m^2$. It is placed in a constant magnetic field of strength $B_0$ which is perpendicular to the plane of the circuit. At time $t = 0$,the magnetic field strength starts increasing linearly as $B = B_0 + \beta t$ with $\beta = 0.04 \ T \ s^{-1}$. The maximum magnitude of the current in the circuit is . . . . $mA$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo