Write limitations of Bernoulli’s theorem.
$(i)$ This theorem is obtained by applying the energy conservation principle, there is an assumption that no energy is lost due to friction. But in fact when fluids flow, some energy does get lost due to internal friction. Infact viscous forces acting between different layers and there layers exert frictional forces on each other resulting in a loss of energy.
$(ii)$ For applying Bernoulli's theorem the fluid must be incompressible, as the elastic energy of the fluid is also not taken into consideration.
A liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the centre of the circular base. If the radius of the vessel is $ r $ and angular velocity of rotation is $\omega $, then the difference in the heights of the liquid at the centre of the vessel and the edge is
The figure shows a liquid of given density flowing steadily in horizontal tube of varying cross-section. Cross sectional areas at $A$ is $1.5\,cm ^2$, and $B$ is $25\,mm ^2$, if the speed of liquid at $B$ is $60\,cm / s$ then $\left( P _{ A }- P _{ B }\right)$ is :(Given $P _{ A }$ and $P _{ B }$ are liquid pressures at $A$ and $B$ points.Density $\rho=1000\,kg\,m ^{-3}$
$A$ and $B$ are on the axis of tube $............\,Pa$
$Assertion :$ The velocity of flow of a liquid is smaller when pressure is larger and vice-versa.
$Reason :$ According to Bernoulli’s theorem, for the stream line flow of an ideal liquid, the total energy per unit mass remains constant.
Give the formula for measurement of velocity of fluid in a broader part of venturi-meter.
A long cylindrical vessel is half filled with a liquid. When the vessel is rotated about its own vertical axis, the liquid rises up near the wall. If the radius of vessel is $5\,cm$ and its rotational speed is $2$ rotations per second, then the difference in the heights between the centre and the sides, in $cm,$ will be