Medium
Write four solutions for the equation: $\pi x + y = 9$
(N/A) To find the solutions for the linear equation $\pi x + y = 9$,we can substitute different values for $x$ and solve for $y$.
$1$. When $x = 0$:
$\pi(0) + y = 9 \Rightarrow 0 + y = 9 \Rightarrow y = 9$.
So,the solution is $(0, 9)$.
$2$. When $x = 1$:
$\pi(1) + y = 9 \Rightarrow \pi + y = 9 \Rightarrow y = 9 - \pi$.
So,the solution is $(1, 9 - \pi)$.
$3$. When $x = 2$:
$\pi(2) + y = 9 \Rightarrow 2\pi + y = 9 \Rightarrow y = 9 - 2\pi$.
So,the solution is $(2, 9 - 2\pi)$.
$4$. When $x = -1$:
$\pi(-1) + y = 9 \Rightarrow -\pi + y = 9 \Rightarrow y = 9 + \pi$.
So,the solution is $(-1, 9 + \pi)$.
$1$. When $x = 0$:
$\pi(0) + y = 9 \Rightarrow 0 + y = 9 \Rightarrow y = 9$.
So,the solution is $(0, 9)$.
$2$. When $x = 1$:
$\pi(1) + y = 9 \Rightarrow \pi + y = 9 \Rightarrow y = 9 - \pi$.
So,the solution is $(1, 9 - \pi)$.
$3$. When $x = 2$:
$\pi(2) + y = 9 \Rightarrow 2\pi + y = 9 \Rightarrow y = 9 - 2\pi$.
So,the solution is $(2, 9 - 2\pi)$.
$4$. When $x = -1$:
$\pi(-1) + y = 9 \Rightarrow -\pi + y = 9 \Rightarrow y = 9 + \pi$.
So,the solution is $(-1, 9 + \pi)$.
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