Express the following linear equation in the form $ax + by + c = 0$ and indicate the values of $a$,$b$,and $c$: $x = 3y$.
(A) The given equation is $x = 3y$.
To express this in the form $ax + by + c = 0$,we subtract $3y$ from both sides:
$x - 3y = 0$
This can be written as:
$(1)x + (-3)y + 0 = 0$
Comparing this with the standard form $ax + by + c = 0$,we get:
$a = 1$
$b = -3$
$c = 0$
To express this in the form $ax + by + c = 0$,we subtract $3y$ from both sides:
$x - 3y = 0$
This can be written as:
$(1)x + (-3)y + 0 = 0$
Comparing this with the standard form $ax + by + c = 0$,we get:
$a = 1$
$b = -3$
$c = 0$
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