Write four solutions for the following equation: $4x - 3y = 24$.

(N/A) Given equation: $4x - 3y = 24$.
Rearranging for $y$:
$3y = 4x - 24$
$y = \frac{4x - 24}{3}$
To find four solutions,we substitute different values for $x$:
$1$. If $x = 0$,then $y = \frac{4(0) - 24}{3} = \frac{-24}{3} = -8$. So,$(0, -8)$ is a solution.
$2$. If $x = 3$,then $y = \frac{4(3) - 24}{3} = \frac{12 - 24}{3} = \frac{-12}{3} = -4$. So,$(3, -4)$ is a solution.
$3$. If $x = 6$,then $y = \frac{4(6) - 24}{3} = \frac{24 - 24}{3} = \frac{0}{3} = 0$. So,$(6, 0)$ is a solution.
$4$. If $x = 9$,then $y = \frac{4(9) - 24}{3} = \frac{36 - 24}{3} = \frac{12}{3} = 4$. So,$(9, 4)$ is a solution.
Thus,four solutions of the given equation are $(0, -8), (3, -4), (6, 0),$ and $(9, 4)$.