Write the bond angle and hybridization type of the water molecule.
(N/A) In the water molecule $(H_2O)$,the oxygen atom is $sp^3$ hybridized.
It has two bond pairs and two lone pairs of electrons,resulting in a bent ($V$-shaped) geometry.
Due to the presence of two lone pairs on the oxygen atom,the bond angle is compressed from the ideal tetrahedral angle of $109.5^{\circ}$ to $104.5^{\circ}$.
It has two bond pairs and two lone pairs of electrons,resulting in a bent ($V$-shaped) geometry.
Due to the presence of two lone pairs on the oxygen atom,the bond angle is compressed from the ideal tetrahedral angle of $109.5^{\circ}$ to $104.5^{\circ}$.
Explore More
Similar Questions
Among the following transformations,the hybridisation of the central atom remains unchanged in
DifficultKVPY 2019
View SolutionIf the dipole moment of an $MX_3$ molecule is zero,then the orbitals used by $M$ $(atomic\ number < 21)$ in sigma bonding are ....
Difficult
View SolutionWhat is the $CORRECT$ geometry and hybridisation for $SF_4$?
Medium
View SolutionWhich of the following has been arranged in increasing order of size of the hybrid orbitals?
Easy
View SolutionThe $AsF_5$ molecule is trigonal bipyramidal. Which of the following orbitals of $As$ are involved in the hybridization?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo