What is the CORRECT geometry and hybridisatio | vedclass

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(C) To determine the geometry and hybridisation of $SF_4$,we first calculate the number of valence electrons: $S$ $(6)$ + $4 	imes F$ $(7)$ = $34$ el

Vedclass · Accepted Answer

See-Saw,$sp^3d$

Vedclass · Answer

(C) To determine the geometry and hybridisation of $SF_4$,we first calculate the number of valence electrons: $S$ $(6)$ + $4 	imes F$ $(7)$ = $34$ electrons.Using the steric number formula: $SN = \frac{1}{2} (V + M - C + A)$,where $V = 6$ (valence electrons of $S$),$M = 4$ (monovalent atoms),$C = 0$,and $A = 0$.$SN = \frac{1}{2} (6 + 4) = 5$.$A$ steric number of $5$ corresponds to $sp^3d$ hybridisation.The molecule has $4$ bonding pairs and $1$ lone pair on the sulfur atom.According to $VSEPR$ theory,the presence of one lone pair in a trigonal bipyramidal electron geometry results in a $See-Saw$ molecular geometry.

What is the $CORRECT$ geometry and hybridisation for $SF_4$?

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