Write the advantages of a potentiometer.
(N/A) potentiometer is a versatile instrument used for measuring potential differences and internal resistance. Its main advantages are:
$1$. It works on the principle of null deflection,meaning no current is drawn from the source of $EMF$ being measured. Therefore,it measures the true $EMF$ of the cell.
$2$. It does not affect the circuit conditions because it does not draw any current from the circuit under test.
$3$. It is highly sensitive and can be used to measure very small potential differences.
$4$. It can be used to compare the EMFs of two cells and to determine the internal resistance of a cell.
$1$. It works on the principle of null deflection,meaning no current is drawn from the source of $EMF$ being measured. Therefore,it measures the true $EMF$ of the cell.
$2$. It does not affect the circuit conditions because it does not draw any current from the circuit under test.
$3$. It is highly sensitive and can be used to measure very small potential differences.
$4$. It can be used to compare the EMFs of two cells and to determine the internal resistance of a cell.
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Similar Questions
The length of a wire of a potentiometer is $100 \, cm$,and the $emf$ of its standard cell is $E \, volt$. It is employed to measure the $emf$ of a battery whose internal resistance is $0.5 \, \Omega$. If the balance point is obtained at $l = 30 \, cm$ from the positive end,the $emf$ of the battery is (where $i$ is the current in the potentiometer wire).
MediumAIEEE 2003
View Solution$A$ null point is obtained at $200 \ cm$ on a potentiometer wire when a cell in the secondary circuit is shunted by $5 \ \Omega$. When a resistance of $15 \ \Omega$ is used for shunting,the null point moves to $300 \ cm$. The internal resistance of the cell is: (in $Omega$)
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Medium
View Solution$A$ cell in a secondary circuit gives a null deflection for $2.5 \ m$ length of a potentiometer wire having a total length of $10 \ m$. If the length of the potentiometer wire is increased by $1 \ m$ without changing the cell in the primary circuit,the new position of the null point is: (in $m$)
DifficultAP EAMCET 2009
View Solution$A$ wire,$10 \ m$ long,has a resistance of $40 \ \Omega$. It is connected in series with a resistance box of resistance $R$ and a $2 \ V$ storage cell. If the potential gradient along the wire is $0.1 \ mV/cm$,then the value of $R$ is (in $Omega$)
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