Write a note on Wurtz Reaction.
Alkyl halides react with sodium in dry ether to give hydrocarbons containing double the number of carbon atoms present in the halide. This reaction is known as Wurtz reaction.
$2 R-X + 2 Na \longrightarrow R-R + 2 NaX$
$2 CH_3-CH_2-Br + 2 Na \xrightarrow{\text{dry ether}} CH_3-CH_2-CH_2-CH_3 + 2 NaBr$
$2 (CH_3)_2CH-Br + 2 Na \xrightarrow{\text{dry ether}} (CH_3)_2CH-CH(CH_3)_2 + 2 NaBr$
$2 R-X + 2 Na \longrightarrow R-R + 2 NaX$
$2 CH_3-CH_2-Br + 2 Na \xrightarrow{\text{dry ether}} CH_3-CH_2-CH_2-CH_3 + 2 NaBr$
$2 (CH_3)_2CH-Br + 2 Na \xrightarrow{\text{dry ether}} (CH_3)_2CH-CH(CH_3)_2 + 2 NaBr$
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Medium
View SolutionGiven below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A):$ $R-I$ undergoes $S_N2$ reaction faster than $R-Cl$.
Reason $(R):$ Iodine is a better leaving group because of its large size.
In the light of the above statements,choose the correct answer from the options given below:
Assertion $(A):$ $R-I$ undergoes $S_N2$ reaction faster than $R-Cl$.
Reason $(R):$ Iodine is a better leaving group because of its large size.
In the light of the above statements,choose the correct answer from the options given below:
MediumNEET 2025
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