Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only?
(N/A) Both oxide $(O^{2-})$ and fluoride $(F^-)$ ions are highly electronegative and have a very small size. Due to these properties,they are able to oxidize the metal to its highest oxidation state.
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Similar Questions
Among $Sc$,$Mn$,$Co$ and $Cu$,identify the element with the highest enthalpy of atomisation. The spin-only magnetic moment value of that element in its $+2$ oxidation state is $......... \text{BM}$ (in nearest integer).
If a titanium compound exhibits a magnetic moment of $1.73 \, B.M.$,what is the oxidation state of $Ti$ in the compound?
Easy
View Solution'Spin only' magnetic moment is same for which of the following ions?
$A$. $Ti^{3+}$ $B$. $Cr^{2+}$ $C$. $Mn^{2+}$ $D$. $Fe^{2+}$ $E$. $Sc^{3+}$
Choose the most appropriate answer from the options given below.
$A$. $Ti^{3+}$ $B$. $Cr^{2+}$ $C$. $Mn^{2+}$ $D$. $Fe^{2+}$ $E$. $Sc^{3+}$
Choose the most appropriate answer from the options given below.
MediumNEET 2024
View SolutionWhich of the following has the maximum number of unpaired electrons?
(Atomic numbers: $Fe=26, Co=27, Mn=25, Cr=24$)
(Atomic numbers: $Fe=26, Co=27, Mn=25, Cr=24$)
Medium
View SolutionIdentify the ferromagnetic element from the following.
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