'Spin only' magnetic moment is same f | vedclass

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Question

lons
			No. of unpaired electrons
			Configuration

$ \mathrm{Ti}^{3+} $
			$1$
			$3 d^1$

$ \mathrm{Cr}^{2+} $
			$4$
			$3

Vedclass · Accepted Answer

$B$ and $D$ only

Vedclass · Answer

lons
			No. of unpaired electrons
			Configuration

$ \mathrm{Ti}^{3+} $
			$1$
			$3 d^1$

$ \mathrm{Cr}^{2+} $
			$4$
			$3 d^4$

$ \mathrm{Mn}^{2+} $
			$5$
			$3 d^5$

$ \mathrm{Fe}^{2+} $
			$4$
			$3 d^6$

$ \mathrm{Sc}^{3+}$
			$0$
			$3 d^0$

Spin only magnetic moment is given by $\sqrt{n(n+2)} \mathrm{BM}$

$	herefore \mathrm{Cr}^{2+}$ and $\mathrm{Fe}^{2+}$ will have same spin only magnetic moment.

'Spin only' magnetic moment is same for which of the following ions?

$A$. $\mathrm{Ti}^{3+}$ $B$. $\mathrm{Cr}^{2+}$ $C$. $\mathrm{Mn}^{2+}$ $D$.$\mathrm{Fe}^{2+}$ $E$. $\mathrm{Sc}^{3+}$

Choose the most appropriate answer from the options given below.