Why do gases always tend to be less soluble i | vedclass

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(N/A) The dissolution of a gas in a liquid is an exothermic process,which can be represented as: $	ext{Gas} + 	ext{Solvent} ightleftharpoons 	ext

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(N/A) The dissolution of a gas in a liquid is an exothermic process,which can be represented as: $\text{Gas} + \text{Solvent} \rightleftharpoons \text{Solution} + \text{Heat}$.
According to Le Chatelier's Principle,if the temperature of a system at equilibrium is increased,the system will shift in the direction that absorbs the added heat.
Since the dissolution process is exothermic,increasing the temperature shifts the equilibrium in the backward direction (towards the gaseous state).
Therefore,the solubility of gases in liquids decreases as the temperature is raised.

Why do gases always tend to be less soluble in liquids as the temperature is raised?

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