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(B) The formula for kinetic energy $(KE)$ is given by $KE = \frac{1}{2}mv^2$,where $m$ is the mass and $v$ is the velocity of the object.$1$. If we do

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Doubling the velocity

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(B) The formula for kinetic energy $(KE)$ is given by $KE = \frac{1}{2}mv^2$,where $m$ is the mass and $v$ is the velocity of the object.$1$. If we double the mass $(m' = 2m)$,the new kinetic energy becomes $KE' = \frac{1}{2}(2m)v^2 = 2 	imes KE$. Thus,the kinetic energy doubles.$2$. If we double the velocity $(v' = 2v)$,the new kinetic energy becomes $KE'' = \frac{1}{2}m(2v)^2 = \frac{1}{2}m(4v^2) = 4 	imes KE$. Thus,the kinetic energy increases four times.Comparing the two,doubling the velocity has a greater effect on the kinetic energy than doubling the mass.

Which would have a greater effect on the kinetic energy of an object - doubling the mass,or doubling the velocity?

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