Which order is correct for the decreasing rea | vedclass

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(B) The reactivity of benzene derivatives toward electrophilic aromatic substitution (like monobromination) depends on the electron density of the rin

Vedclass · Accepted Answer

$I > III > II > IV$

Vedclass · Answer

(B) The reactivity of benzene derivatives toward electrophilic aromatic substitution (like monobromination) depends on the electron density of the ring.$1$. $C_6H_5CH_3$ (Toluene): The $-CH_3$ group is an electron-donating group $(EDG)$ via hyperconjugation and inductive effect,which activates the ring.$2$. $C_6H_6$ (Benzene): This is the reference compound with no substituents.$3$. $C_6H_5COOH$ (Benzoic acid): The $-COOH$ group is an electron-withdrawing group $(EWG)$ via resonance and inductive effect,which deactivates the ring.$4$. $C_6H_5NO_2$ (Nitrobenzene): The $-NO_2$ group is a strong electron-withdrawing group $(EWG)$ via resonance and inductive effect,which strongly deactivates the ring.Thus,the order of decreasing reactivity is $I > III > II > IV$.

Which order is correct for the decreasing reactivity toward ring monobromination of the following compounds:
$I. \, C_6H_5CH_3$
$II. \, C_6H_5COOH$
$III. \, C_6H_6$
$IV. \, C_6H_5NO_2$

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Which order is correct for the decreasing reactivity toward ring monobromination of the following compounds:$I. \, C_6H_5CH_3$$II. \, C_6H_5COOH$$III. \, C_6H_6$$IV. \, C_6H_5NO_2$