An aromatic compound of molecular formula C_6 | vedclass

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Question

(A) The number of isomers formed upon nitration depends on the number of non-equivalent positions available in the benzene ring for electrophilic subs

Vedclass · Accepted Answer

$o$-dibromobenzene

Vedclass · Answer

(A) The number of isomers formed upon nitration depends on the number of non-equivalent positions available in the benzene ring for electrophilic substitution.For $o$-dibromobenzene ($1,2$-dibromobenzene),there are $3$ non-equivalent positions available for nitration,yielding $3$ isomers.For $m$-dibromobenzene ($1,3$-dibromobenzene),there are $4$ non-equivalent positions available,yielding $4$ isomers.For $p$-dibromobenzene ($1,4$-dibromobenzene),there is only $1$ non-equivalent position available,yielding $1$ isomer.Since the question states that $3$ isomers were obtained,the original compound must be $o$-dibromobenzene.

An aromatic compound of molecular formula $C_6H_4Br_2$ was nitrated,and three isomers of formula $C_6H_3Br_2NO_2$ were obtained. The original compound is:

Similar Questions

An aromatic compound,among other things,should have a $\pi$-electron cloud containing $(4n + 2)$ electrons,where $n$ cannot be:

When acetylene is passed through a red hot iron tube,compound $X$ is formed. Which one of the following reactions will yield $X$ as the major product?

Which of the following compounds or ions is not aromatic?

What is the major product $X$ in the following reaction?
$\text{Benzene} + CH_3CH_2CH_2Cl \xrightarrow{AlCl_3} (X)$

$x =$ Number of aromatic compounds obtained when the above compound undergoes complete acidic hydrolysis.

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