Which one statement is correct? A parallel pl | vedclass

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(D) When a dielectric slab is inserted into a parallel plate capacitor while the battery remains connected,the potential difference $V$ across the pla

Vedclass · Accepted Answer

Both $(a)$ and $(b)$

Vedclass · Answer

(D) When a dielectric slab is inserted into a parallel plate capacitor while the battery remains connected,the potential difference $V$ across the plates remains constant,i.e.,$V = {V_0}$.Since the capacitance $C$ increases by a factor of $K$ (dielectric constant),where $C = KC_0$,the charge $Q$ on the plates increases according to $Q = CV = K C_0 V_0 = K Q_0$. Thus,$Q > {Q_0}$.The electric field $E$ between the plates is given by $E = V/d$. Since $V$ and $d$ remain constant,$E = {E_0}$.The energy stored in the capacitor is $U = \frac{1}{2}CV^2$. Since $C$ increases and $V$ remains constant,$U$ increases,i.e.,$U > {U_0}$.Therefore,both statements $(a)$ and $(b)$ are correct.

Similar Questions

Write the formula for the capacitance of a capacitor having a dielectric constant $K = 2$.

$A$ parallel plate capacitor is charged and then isolated. If the separation between the plates is increased,which one of the following statements is $NOT$ correct?

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