Which one of the following statements is not | vedclass

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(C) The correct statement analysis is as follows:$1$. The molecular formula of calgon is $Na_2[Na_4(PO_3)_6]$,which is correct.$2$. Beryllium halides

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Among alkali metals,the reducing property of sodium is least in aqueous solution

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(C) The correct statement analysis is as follows:$1$. The molecular formula of calgon is $Na_2[Na_4(PO_3)_6]$,which is correct.$2$. Beryllium halides are covalent in nature due to the small size and high polarizing power of $Be^{2+}$ ions,making them soluble in organic solvents,which is correct.$3$. Among alkali metals,Lithium $(Li)$ has the highest reducing property in aqueous solution due to its high hydration energy. Sodium $(Na)$ does not have the least reducing property; the trend is $Li > K > Rb > Cs > Na$. Thus,the statement is incorrect.$4$. White metal (also known as Babbitt metal) is an alloy typically composed of tin,copper,and antimony,not Lithium. This statement is also incorrect.However,in the context of standard competitive chemistry questions,the most widely recognized incorrect statement regarding the specific properties of alkali metals is that sodium has the least reducing property,as it contradicts the standard electrochemical series behavior in aqueous media.

Elements	Flame Color
$1$. $Li$	$a$. Yellow
$2$. $Na$	$b$. Red-violet
$3$. $Rb$	$c$. Blue
$4$. $Cs$	$d$. Crimson red

Which one of the following statements is not correct?

Similar Questions

Assertion $A$: Alkali metals impart characteristic colors to the flame in the flame test.
Reason $R$: They have very low ionization enthalpy.

The correct order of solubility for the given compounds is:

The blue color of a solution of sodium in liquid ammonia is due to:

Match the following:
Elements Flame Color
$1$. $Li$ $a$. Yellow
$2$. $Na$ $b$. Red-violet
$3$. $Rb$ $c$. Blue
$4$. $Cs$ $d$. Crimson red

If $Na$ is heated in the presence of air,it forms:

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