Which one of the following is not bounded on the intervals as indicated?

  • A
    $f(x) = 2^{\frac{1}{x - 1}}$ on $(0, 1)$
  • B
    $g(x) = x \cos \frac{1}{x}$ on $(-\infty, \infty)$
  • C
    $h(x) = x e^{-x}$ on $(0, \infty)$
  • D
    $l(x) = \tan^{-1} 2^x$ on $(-\infty, \infty)$

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Answer the following by appropriately matching the lists based on the information given in the paragraph.
Let $f(x) = \sin(\pi \cos x)$ and $g(x) = \cos(2\pi \sin x)$ be two functions defined for $x > 0$. Define the following sets whose elements are written in increasing order:
$X = \{x : f(x) = 0\}, Y = \{x : f'(x) = 0\}$
$Z = \{x : g(x) = 0\}, W = \{x : g'(x) = 0\}$
$List-I$ contains the sets $X, Y, Z$ and $W$. $List-II$ contains some information regarding these sets.
$List-I$$List-II$
$(I) X$$(P) \supseteq \{\frac{\pi}{2}, \frac{3\pi}{2}, 4\pi, 7\pi\}$
$(II) Y$$(Q) \text{ an arithmetic progression}$
$(III) Z$$(R) \text{ NOT an arithmetic progression}$
$(IV) W$$(S) \supseteq \{\frac{\pi}{6}, \frac{7\pi}{6}, \frac{13\pi}{6}\}$
$(T) \supseteq \{\frac{\pi}{3}, \frac{2\pi}{3}, \pi\}$
$(U) \supseteq \{\frac{\pi}{6}, \frac{3\pi}{4}\}$

$(1)$ Which of the following is the only $CORRECT$ combination?
$(1) (II), (R), (S)$ $(2) (I), (P), (R)$ $(3) (II), (Q), (T)$ $(4) (I), (Q), (U)$
$(2)$ Which of the following is the only $CORRECT$ combination?
$(1) (IV), (Q), (T)$ $(2) (IV), (P), (R), (S)$ $(3) (III), (R), (U)$ $(4) (III), (P), (Q), (U)$

If $f: R \setminus \{0\} \rightarrow R$ is defined by $f(x) = x + \frac{1}{x}$,then the value of $(f(x))^2 =$

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