Which one of the following constitutes a group of the isoelectronic species?
- A$C_2^{2-}, O_2^-, CO, NO$
- B$NO^{+}, C_2^{2-}, CN^{-}, N_2$
- C$CN^{-}, N_2, O_2^{2-}, C_2^{2-}$
- D$N_2, O_2^-, NO^{+}, CO$
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Similar Questions
The number of paramagnetic species among the following is $......$
$B_{2}, Li_{2}, C_{2}, C_{2}^{-}, O_{2}^{2-}, O_{2}^{+},$ and $He_{2}^{+}$
$B_{2}, Li_{2}, C_{2}, C_{2}^{-}, O_{2}^{2-}, O_{2}^{+},$ and $He_{2}^{+}$
Arrange the following in the correct order of their bond orders.
$I. N_2, II. O_2, III. O_2^+, IV. O_2^-$
$I. N_2, II. O_2, III. O_2^+, IV. O_2^-$
The correct set of symbols for the molecular orbitals given below is:
When $N_2$ goes to $N_2^+$, the $N-N$ bond distance ..... and when $O_2$ goes to $O_2^+$, the $O-O$ bond distance .......
MediumIIT 1996
View SolutionDuring the formation of a molecular orbital from atomic orbitals,the probability of electron density is
Medium
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