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(C) Bond order is defined as the number of chemical bonds present between two atoms of a molecule.Using Molecular Orbital Theory $(MOT)$:$I. N_2$ ($14

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$I > III > II > IV$

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(C) Bond order is defined as the number of chemical bonds present between two atoms of a molecule.Using Molecular Orbital Theory $(MOT)$:$I. N_2$ ($14$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^2$. Bond order $= \frac{10-4}{2} = 3$.$II. O_2$ ($16$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$. Bond order $= \frac{10-6}{2} = 2$.$III. O_2^+$ ($15$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1$. Bond order $= \frac{10-5}{2} = 2.5$.$IV. O_2^-$ ($17$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^1$. Bond order $= \frac{10-7}{2} = 1.5$.Comparing the bond orders: $3 (I) > 2.5 (III) > 2 (II) > 1.5 (IV)$.Thus,the correct order is $I > III > II > IV$.

Arrange the following in the correct order of their bond orders.
$I. N_2, II. O_2, III. O_2^+, IV. O_2^-$

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Arrange the following in the correct order of their bond orders.$I. N_2, II. O_2, III. O_2^+, IV. O_2^-$