Which one is the electronic configuration of | vedclass

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(A) The atomic number of iron $(Fe)$ is $26$. The ground state electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$ or $1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^

Vedclass · Accepted Answer

$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^6$

Vedclass · Answer

(A) The atomic number of iron $(Fe)$ is $26$. The ground state electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$ or $1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^6 4s^2$. When $Fe$ forms the $Fe^{2+}$ ion,it loses two electrons from the outermost shell,which is the $4s$ orbital. Therefore,the electronic configuration of $Fe^{2+}$ becomes $[Ar] 3d^6$ or $1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^6$.

Which one is the electronic configuration of $Fe^{2+}$?

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