The correct order of energy for orbitals is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the $(n+l)$ rule,the energy of an orbital increases as the value of $(n+l)$ increases.For a given $(n+l)$ value,the orbital with the

Vedclass · Accepted Answer

$ns < np < (n-1)d < (n-2)f$

Vedclass · Answer

(A) According to the $(n+l)$ rule,the energy of an orbital increases as the value of $(n+l)$ increases.For a given $(n+l)$ value,the orbital with the lower $n$ value has lower energy.Following the Aufbau principle,the sequence of energy levels is $ns However,based on the $(n+l)$ rule,the general increasing order of energy is $ns < (n-2)f < (n-1)d < np$ is not universally true for all $n$. Given the options,the standard order of increasing energy is $ns < (n-2)f < (n-1)d < np$ is often represented as $ns < (n-2)f < (n-1)d < np$.

Similar Questions

Degenerate atomic orbitals have

If the nitrogen atom had electronic configuration $1s^7$,it would have energy lower than that of the normal ground state configuration $1s^2, 2s^2, 2p^3$ because the electrons would be closer to the nucleus. Yet,$1s^7$ is not observed because it violates:

Write the values of $n, l, m_{l}, m_{s}$ for $4f$.

The energy of an electron of $2p_y$ orbital is

Identify the orbital having the lowest energy from the following.

Vedclass Test Series

Exam Paper Generator

Online Exam Module