Which one has the highest boiling point?

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(C) The boiling point elevation is a colligative property,which depends on the van't Hoff factor $(i)$.For $0.1 \ N \ Na_2SO_4$,$i = 3$ and molarity $

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$0.1 \ M \ Al_2(SO_4)_3$

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(C) The boiling point elevation is a colligative property,which depends on the van't Hoff factor $(i)$.For $0.1 \ N \ Na_2SO_4$,$i = 3$ and molarity $= 0.05 \ M$,so $i 	imes M = 0.15$.For $0.1 \ N \ MgSO_4$,$i = 2$ and molarity $= 0.05 \ M$,so $i 	imes M = 0.10$.For $0.1 \ M \ Al_2(SO_4)_3$,$i = 5$ and molarity $= 0.1 \ M$,so $i 	imes M = 0.50$.For $0.1 \ M \ BaSO_4$,it is sparingly soluble,so $i 	imes M$ is very low.Since $Al_2(SO_4)_3$ has the highest value of $i 	imes M$,it will show the highest boiling point.

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