For 0.1 M solutions of the following electro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Colligative properties are directly proportional to the van't Hoff factor $(i)$ for solutions of the same concentration.$1.$ For $NaCl$: $NaCl 	o

Vedclass · Accepted Answer

$NaCl < Na_2SO_4 < Na_3PO_4$

Vedclass · Answer

(B) Colligative properties are directly proportional to the van't Hoff factor $(i)$ for solutions of the same concentration.$1.$ For $NaCl$: $NaCl 	o Na^{+} + Cl^{-}$,so $i = 2$.$2.$ For $Na_2SO_4$: $Na_2SO_4 	o 2Na^{+} + SO_4^{2-}$,so $i = 3$.$3.$ For $Na_3PO_4$: $Na_3PO_4 	o 3Na^{+} + PO_4^{3-}$,so $i = 4$.Since the colligative property depends on the number of particles,the order is $NaCl < Na_2SO_4 < Na_3PO_4$ $(2 < 3 < 4)$.

For $0.1 \ M$ solutions of the following electrolytes,the colligative property will follow the order:

Similar Questions

$A$ $0.5 \ m$ aqueous solution of a weak acid $(HX)$ is $20\%$ ionized. If $K_f$ for water is $1.86 \ K \ kg \ mol^{-1}$,the depression in freezing point of the solution is ....... $K$.

Which of the following aqueous solutions has the highest freezing point?

Which of the following has the same van't Hoff factor $(i)$ as $K_3[Fe(CN)_6]$?

Which of the following $0.1 \ M$ solutions will exhibit the minimum freezing point?

Which of the following will have the highest boiling point at $1 \ atm$ pressure?

Vedclass Test Series

Exam Paper Generator

Online Exam Module