A cable of resistance 10,Omega carries electr | vedclass

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(A) The electric power $P$ produced by the generator is given by $P = 250\,kW = 250,000\,W$.The voltage $V$ at which the power is transmitted is $V =

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$25$

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(A) The electric power $P$ produced by the generator is given by $P = 250\,kW = 250,000\,W$.The voltage $V$ at which the power is transmitted is $V = 10,000\,V$.The relationship between power,voltage,and current is given by the formula $P = VI$.To find the current $I$,we rearrange the formula: $I = \frac{P}{V}$.Substituting the given values: $I = \frac{250,000\,W}{10,000\,V} = 25\,A$.Therefore,the current in the cable is $25\,A$.

$A$ cable of resistance $10\,\Omega$ carries electric power from a generator producing $250\,kW$ at $10000\,V$. The current in the cable is ............. $A$.

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