Which of the following will NOT undergo S_{N} | vedclass

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Question

(D) The $S_{N}1$ reaction mechanism proceeds via the formation of a carbocation intermediate. The stability of the carbocation determines the reactivi

Vedclass · Accepted Answer

$C_6H_5CH_2CH_2Cl$

Vedclass · Answer

(D) The $S_{N}1$ reaction mechanism proceeds via the formation of a carbocation intermediate. The stability of the carbocation determines the reactivity towards $S_{N}1$. $(A)$ $C_6H_5CH_2Cl$ forms a resonance-stabilized benzyl carbocation $(C_6H_5CH_2^+)$. $(B)$ $CH_2=CHCH_2Cl$ forms a resonance-stabilized allyl carbocation $(CH_2=CHCH_2^+)$. $(C)$ $(CH_3)_3CCl$ forms a stable tertiary carbocation $((CH_3)_3C^+)$. $(D)$ $C_6H_5CH_2CH_2Cl$ is a primary alkyl halide. The formation of a primary carbocation $(C_6H_5CH_2CH_2^+)$ is highly unfavorable due to its low stability. Therefore,it does not undergo $S_{N}1$ reaction.

Which of the following will $NOT$ undergo $S_{N}1$ reaction with $\text{OH}^-$?

Similar Questions

The major product formed in the reaction is:
$C_6H_5OCH_3 + (CH_3)_2CHCH_2Br \xrightarrow{AlCl_3}$

Which among the following is $NOT$ a correct statement about $S_{N}1$ reaction?

Number of moles of $AgCl$ formed in the following reaction is $X$. Identify $X$ from the given reaction.

What are $X, Y$ and $Z$ in the following reactions?
$(CH_3)_3 C-O^- Na^+ + CH_3 CH_2 Br \longrightarrow X + NaBr$
$(CH_3)_3 C-Br + CH_3 CH_2 O^- Na^+ \longrightarrow Y + Z$

What is the decreasing order of nucleophilicity for the following nucleophiles?
$1. CH_3COO^-$
$2. CH_3O^-$
$3. CN^-$
$4. CH_3-C_6H_4-SO_3^-$ (tosylate ion)

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