Number of moles of AgCl formed in the followi | vedclass

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(C) The reaction of organic halides with $AgNO_3$ proceeds via the formation of carbocations. Only those chlorine atoms that can form stable carbocati

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) The reaction of organic halides with $AgNO_3$ proceeds via the formation of carbocations. Only those chlorine atoms that can form stable carbocations (like benzylic or tertiary) or are easily ionizable will react with $AgNO_3$ to precipitate $AgCl$. $1$. The chlorine atom on the benzene ring (aryl chloride) is not reactive towards $AgNO_3$ due to partial double bond character. $2$. The vinylic chlorine atom is also not reactive. $3$. The secondary benzylic chlorine atom forms a stable benzylic carbocation,which reacts with $AgNO_3$ to give $1$ mole of $AgCl$. $4$. The tertiary alkyl chlorine atom forms a stable tertiary carbocation,which reacts with $AgNO_3$ to give $1$ mole of $AgCl$. Thus,a total of $2$ moles of $AgCl$ are formed. Therefore,$X = 2$.

Number of moles of $AgCl$ formed in the following reaction is $X$. Identify $X$ from the given reaction.

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