Which of the following will not give the same | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Hydroboration-oxidation follows anti-Markownikoff's rule (syn-addition of $H$ and $OH$),while acid-catalysed hydration follows Markownikoff's rule

Vedclass · Accepted Answer

$1-$Methylcyclohexene

Vedclass · Answer

(B) Hydroboration-oxidation follows anti-Markownikoff's rule (syn-addition of $H$ and $OH$),while acid-catalysed hydration follows Markownikoff's rule and involves a carbocation intermediate,which may undergo rearrangement.For symmetric alkenes like $CH_2=CH_2$ or $CH_3-CH=CH-CH_3$,both processes yield the same product.For cyclic alkenes like cyclohexene,the products are the same (cyclohexanol).However,for unsymmetrical alkenes like $1$-methylcyclohexene,acid-catalysed hydration leads to a more stable tertiary carbocation,resulting in $1$-methylcyclohexanol,whereas hydroboration-oxidation adds $OH$ to the less substituted carbon,resulting in $2$-methylcyclohexanol. Thus,they give different products.

Which of the following will not give the same product on hydroboration-oxidation and acid-catalysed hydration?

Similar Questions

Identify the product $A$ in the following reaction:
$Methylenecyclohexane \xrightarrow{Br_2 / H_2O} A$

$CH_3-CH=CH_2 \xrightarrow{HBr} \text{Major product } (A). \text{ } A \text{ is:}$

Identify the product in the following reaction.

In the hydroboration-oxidation reaction of propene with diborane,$H_2O_2$,and $NaOH$,the organic compound formed is:

$1, 2$-dibromocyclohexane on dehydrohalogenation gives

Vedclass Test Series

Exam Paper Generator

Online Exam Module