CH_3-CH=CH_2 xrightarrow{HBr} text{Major prod | vedclass

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(A) The reaction of propene $(CH_3-CH=CH_2)$ with $HBr$ is an electrophilic addition reaction.According to Markovnikov's rule,the electrophile $H^+$ a

Vedclass · Accepted Answer

$CH_3-CH(Br)-CH_3$

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(A) The reaction of propene $(CH_3-CH=CH_2)$ with $HBr$ is an electrophilic addition reaction.According to Markovnikov's rule,the electrophile $H^+$ adds to the carbon atom having more hydrogen atoms to form the more stable carbocation.Here,the secondary carbocation $(CH_3-CH^+-CH_3)$ is more stable than the primary carbocation $(CH_3-CH_2-CH_2^+)$.Therefore,the bromide ion $(Br^-)$ attacks the secondary carbocation to form $2$-bromopropane $(CH_3-CH(Br)-CH_3)$ as the major product.

$CH_3-CH=CH_2 \xrightarrow{HBr} \text{Major product } (A). \text{ } A \text{ is:}$

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