Which of the following statements is not true | vedclass

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(D) The correct answer is $D$. $A$. $MnCl_4^{2-}$: $Mn$ is in $+2$ oxidation state $(d^5)$. $Cl^-$ is a weak field ligand,leading to $sp^3$ hybridizat

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$[Ni(PPh_3)_2Br_2]$ has trigonal bipyramidal geometry and one unpaired electron.

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(D) The correct answer is $D$. $A$. $MnCl_4^{2-}$: $Mn$ is in $+2$ oxidation state $(d^5)$. $Cl^-$ is a weak field ligand,leading to $sp^3$ hybridization and tetrahedral geometry. It has $5$ unpaired electrons,so it is paramagnetic. This statement is true.$B$. $[Mn(CN)_6]^{2-}$: $Mn$ is in $+4$ oxidation state $(d^3)$. It forms an octahedral complex ($d^2sp^3$ or $sp^3d^2$). It has $3$ unpaired electrons,so it is paramagnetic. This statement is true.$C$. $[CuCl_4]^{2-}$: $Cu$ is in $+2$ oxidation state $(d^9)$. It is a tetrahedral complex ($sp^3$ hybridization). However,the statement claims square planar geometry,which is incorrect for $[CuCl_4]^{2-}$. Note: $[CuCl_4]^{2-}$ is actually tetrahedral. Wait,checking the options: $[Ni(PPh_3)_2Br_2]$ is a $4$-coordinate complex,which is tetrahedral,not trigonal bipyramidal. Thus,$D$ is definitely false.$D$. $[Ni(PPh_3)_2Br_2]$: $Ni$ is in $+2$ oxidation state $(d^8)$. It is a $4$-coordinate complex,which typically adopts tetrahedral geometry,not trigonal bipyramidal. Therefore,this statement is false.

List-$I$ (Compound)	List-$II$ (Hybridization of Central atom)
$A. [Ni(NH_3)_6]^{2+}$	$1. sp^3$
$B. [PtCl_4]^{2-}$	$2. sp^3d^2$
$C. [Ni(CO)_4]$	$3. dsp^2$
$D. [Co(ox)_3]^{3-}$	$4. d^2sp^3$

Which of the following statements is not true?

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