Which of the following statements are not cor | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) is incorrect: For water,$K_f = 1.86 	ext{ K kg mol}^{-1}$ and $K_b = 0.512 	ext{ K kg mol}^{-1}$,so $K_f > K_b$.$B$ is incorrect: Since $K_f > K

Vedclass · Accepted Answer

$A, B$ and $D$ only

Vedclass · Answer

(C) is incorrect: For water,$K_f = 1.86 	ext{ K kg mol}^{-1}$ and $K_b = 0.512 	ext{ K kg mol}^{-1}$,so $K_f > K_b$.$B$ is incorrect: Since $K_f > K_b$,the depression in freezing point $(\Delta T_f = K_f m)$ is larger than the elevation in boiling point $(\Delta T_b = K_b m)$ for the same molality $m$.$C$ is correct: Osmotic pressure is preferred because its magnitude is large even for dilute solutions,making it easier to measure for macromolecules like proteins and polymers.$D$ is incorrect: The dimerised form of benzoic acid involves hydrogen bonding between the carboxyl groups,represented as $(C_6H_5COOH)_2$ with the structure $C_6H_5 - C(OH)=O \cdots HO - C(O) - C_6H_5$.Therefore,statements $A, B$,and $D$ are incorrect.

Similar Questions

$A$ solution of urea (molar mass $60 \, g \, mol^{-1}$) boils at $100.18 \, ^oC$ at atmospheric pressure. If $K_f$ and $K_b$ for water are $1.86$ and $0.512 \, K \, kg \, mol^{-1}$ respectively,the above solution will freeze at ........... $^oC$.

Which of the following mixtures is known as Proof Spirit (by volume)?

Select the correct statement.

$100 \ g$ each of two solutions,one containing $20 \%$ by mass of $NaOH$ and the other $40 \%$ by mass of $NaOH$,are mixed. The density of the resulting solution is $1.25 \ g/mL$. Find the new $\% \ w/v$ of $NaOH$ in the final solution.

If the freezing point of an aqueous solution of salt $MX_4$ $(\alpha = 90\%)$ is $-3\ ^oC$,then its boiling point will be ........ $^oC$. (Assume it is $100\%$ ionized at the boiling temperature and $k_f = 1.86\ K\ kg\ mol^{-1}$,$k_b = 0.52\ K\ kg\ mol^{-1}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module