Which of the following statements is correct | vedclass

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(D) For $I^{+}_3$: The central $I$ atom has $2$ bond pairs and $2$ lone pairs. Hybridization is $sp^3$. The geometry is bent,making it a polar species

Vedclass · Accepted Answer

Both are planar species

Vedclass · Answer

(D) For $I^{+}_3$: The central $I$ atom has $2$ bond pairs and $2$ lone pairs. Hybridization is $sp^3$. The geometry is bent,making it a polar species $(\mu 
eq 0)$. It is a planar species.For $I^{-}_3$: The central $I$ atom has $2$ bond pairs and $3$ lone pairs. Hybridization is $sp^3d$. The geometry is linear,making it a non-polar species $(\mu = 0)$. It is a planar species.Comparing both: Both $I^{+}_3$ and $I^{-}_3$ are planar species. Thus,option $D$ is correct.

List-$I$ (Compound / Species)	List-$II$ (Shape / Geometry)
$A$. $SF_4$	$I$. Tetrahedral
$B$. $BrF_3$	$II$. Pyramidal
$C$. $BrO_3^{-}$	$III$. See-saw
$D$. $NH_4^{+}$	$IV$. Bent $T$-shape

Which of the following statements is correct about $I^{+}_3$ and $I^{-}_3$ molecular ions?

Similar Questions

Amongst the following,the number of species having a linear shape is $...........$
$XeF_2, I_3^{+}, C_3O_2, I_3^{-}, CO_2, SO_2, BeCl_2$ and $BCl_2^{\Theta}$

Which of the following molecules contains one pair of non-bonding electrons?

Match List-$I$ with List-$II$ :

List-$I$ (Compound / Species) List-$II$ (Shape / Geometry)

$A$. $SF_4$ $I$. Tetrahedral

$B$. $BrF_3$ $II$. Pyramidal

$C$. $BrO_3^{-}$ $III$. See-saw

$D$. $NH_4^{+}$ $IV$. Bent $T$-shape

Choose the correct answer from the options given below :

Which of the following pairs is isostructural?

Consider the species $CH_4$,$NH_4^+$ and $BH_4^-$. Choose the correct option with respect to these species.

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